제출 #1003472

#제출 시각아이디문제언어결과실행 시간메모리
1003472amine_arouaGap (APIO16_gap)C++17
100 / 100
42 ms2824 KiB
#include <bits/stdc++.h> using namespace std; #define intt long long #define fore(i , n) for(int i = 0 ; i < n; i++) #define forr(i , x ,y) for(int i = x; i <= y;i++) #define pb push_back void MinMax(intt s , intt t , intt *mn , intt *mx); long long findGap(int T, int N) { if(T == 1) { intt mn = 0 , mx = 1e18*1LL; vector<intt> a; int n = N; while(n) { MinMax(mn , mx , &mn , &mx); a.pb(mn); n--; if(mn == mx) break; a.pb(mx); n--; mn++; mx--; } sort(a.begin() , a.end()); intt ans = 0; fore(i , N - 1) { ans = max(ans , a[i + 1] - a[i]); } return ans; } intt mn , mx; MinMax(0ll , 1LL * 1e18 , &mn , &mx); intt gmn = mn , gmx = mx; intt d = (mx - mn + N - 2)/((N - 1)); vector<intt> MinB(N , -1) , MaxB(N , -1); fore(i , N - 1) { intt lt = i * d + gmn , rt = (i + 1)*d + gmn - 1; MinMax(lt , rt , &mn , &mx); MinB[i] = mn; MaxB[i] = mx; } if((N - 1) * d + gmn <= gmx) MinB[N - 1]= MaxB[N - 1] = gmx; intt prv = MaxB[0]; intt ans = (intt)d; forr(i , 1 , N - 1) { if(MinB[i] == -1) continue; ans = max(ans , MaxB[i] - MinB[i]); ans= max(ans , MinB[i] - prv); prv = MaxB[i]; } return ans; }
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