Submission #1002076

#TimeUsernameProblemLanguageResultExecution timeMemory
1002076TobEaster Eggs (info1cup17_eastereggs)C++14
100 / 100
11 ms504 KiB
#include <bits/stdc++.h> #include "grader.h" #define F first #define S second #define all(x) x.begin(), x.end() #define pb push_back #define FIO ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0) using namespace std; typedef long long ll; typedef pair <int, int> pii; using namespace std; /* static int N, X, cntQ; static vector < int > v[1009]; int query (vector < int > h) { cntQ ++; int ap[1009]; if (h.empty ()) return 0; for (int i=1; i<=N; i++) ap[i] = 0; for (auto it = h.begin (); it != h.end (); it ++) ap[*it] = 1; queue < int > cc; cc.push (h[0]), ap[h[0]] = 2; while (!cc.empty ()) { int nod = cc.front (); cc.pop (); for (auto it = v[nod].begin (); it != v[nod].end (); it ++) if (ap[*it] == 1) ap[*it] = 2, cc.push (*it); } for (int i=1; i<=N; i++) if (ap[i] == 1) return -1; for (auto it = h.begin (); it != h.end (); it ++) if (*it == X) return 1; return 0; }*/ //---------------------------- const int maxn = 512; int tim, st[maxn]; vector <int> adj[maxn]; void dfs(int x, int p = -1) { st[tim++] = x; for (int y : adj[x]) if (y != p) dfs(y, x); } int findEgg(int n, vector <pii> e) { tim = 0; for (int i = 0; i < n; i++) adj[i].clear(); for (int i = 0; i < n-1; i++) { adj[e[i].F-1].pb(e[i].S-1); adj[e[i].S-1].pb(e[i].F-1); } int lo = 0, hi = n-1; dfs(0); while (lo < hi) { int mid = (lo + hi) / 2; vector <int> v; for (int i = 0; i <= mid; i++) v.pb(st[i]+1); if (query(v)) hi = mid; else lo = mid+1; } return st[lo]+1; } //---------------------------- /* int main () { //freopen ("input", "r", stdin); //freopen ("output", "w", stdout); scanf ("%d", &N); int Queries; vector < pair < int, int > > param; for (int i=1; i<N; i++) { int x, y; scanf ("%d %d", &x, &y); v[x].push_back (y); v[y].push_back (x); param.push_back ({x, y}); } scanf ("%d", &Queries); while (Queries --) { scanf ("%d", &X), cntQ = 0; int Y = findEgg (N, param); if (X != Y) { printf ("WA %d instead of %d\n", Y, X); return 0; } printf ("OK %d\n", cntQ); } return 0; }*/
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