# | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 |
---|---|---|---|---|---|---|---|
1000787 | uranhishig | 경주 (Race) (IOI11_race) | C++14 | 0 ms | 0 KiB |
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<vi> vvi;
typedef vector<vl> vvl;
typedef pair<int,int> pii;
typedef pair<double, double> pdd;
typedef pair<ll, ll> pll;
typedef vector<pii> vii;
typedef vector<pll> vll;
typedef double dl;
#define f first
#define s second
#define mp make_pair
#define pb push_back
#define all(a) (a).begin(),(a).end()
#define sz(x) (int)x.size()
#define mid(l,r) ((r+l)/2)
#define left(node) (node*2)
#define right(node) (node*2+1)
#define mx_int_prime 999999937
#define mod 1000000007
#define mem(a,b) memset(a, b, sizeof(a) )
#define gcd(a,b) __gcd(a,b)
#define lcm(a, b) (a * b) / gcd(a, b)
#define sqr(a) ((a) * (a))
#define faster ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define fastio cin.tie(0)->sync_with_stdio(0)
#define print(x) cout << x << "\n"
#define rep(i, n) for(int i = 0; i < (n); i++)
#define rep1(i, n) for(int i = 1; i <= (n); i++)
#define yes cout << "YES" << endl;
#define no cout << "NO" << endl;
const int MAXN = 1e6;
vector<pair<int, int>> adj[MAXN];
bool visited[MAXN];
int mi = INT_MAX;
void dfs(int node, int x, int y, int z) {
visited[node] = true;
if (x == y) {
mi = min(mi, z);
}
else {
for (auto neighbor : adj[node]) {
int nextCity = neighbor.f;
int length = neighbor.s;
if (!visited[nextCity] && x + length <= y) {
dfs(nextCity, x + length, y, z + 1);
}
}
}
visited[node] = false;
}
int run(int N, int K, int H[][2], int L[]) {
rep(i, N-1) {
int city1 = H[i][0], city2 = H[i][1], length = L[i];
adj[city1].emplace_back(city2, length);
adj[city2].emplace_back(city1, length);
}
mi = INT_MAX;
for (int startCity = 0; startCity < N; ++startCity) {
memset(visited, false, sizeof(visited));
dfs(startCity, 0, K, 0);
}
if (mi == INT_MAX) {
return -1;
} else {
return mi;
}
}