제출 #1000185

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
1000185		whatthemomooofun1729	Mag (COCI16_mag)	C++17	60 / 120	340 ms	248656 KiB

mag

#include <iostream>
#include <algorithm>
#include <utility>
#include <vector>
#include <stack>
#include <map>
#include <queue>
#include <set>
#include <unordered_set>
#include <unordered_map>
#include <cstring>
#include <cmath>
#include <functional>
#include <cassert>
#include <iomanip>
#include <numeric>
#include <bitset>
#include <sstream>
#include <chrono>
#include <random>

#define ff first
#define ss second
#define PB push_back
#define sz(x) int(x.size())
#define rsz resize
#define fch(xxx, yyy) for (auto xxx : yyy) // abusive notation
#define all(x) (x).begin(),(x).end()
#define eps 1e-9

// more abusive notation (use at your own risk):
//#define int ll

using namespace std;
typedef long long ll;
typedef long double ld;
typedef unsigned long long ull;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
using vi = vector<int>;
using vll = vector<ll>;

// debugging
void __print(int x) {std::cerr << x;}
void __print(ll x) {std::cerr << x;} /* remember to uncomment this when not using THE MACRO */
void __print(unsigned x) {std::cerr << x;}
void __print(ull x) {std::cerr << x;}
void __print(float x) {std::cerr << x;}
void __print(double x) {std::cerr << x;}
void __print(ld x) {std::cerr << x;}
void __print(char x) {std::cerr << '\'' << x << '\'';}
void __print(const char *x) {std::cerr << '\"' << x << '\"';}
void __print(const string& x) {std::cerr << '\"' << x << '\"';}
void __print(bool x) {cerr << (x ? "true" : "false");}
template<typename T, typename V> void __print(const pair<T, V> &x) {std::cerr << '{'; __print(x.ff); std::cerr << ", "; __print(x.ss); std::cerr << '}';}
template<typename T> void __print(const T& x) {int f = 0; std::cerr << '{'; for (auto &i: x) std::cerr << (f++ ? ", " : ""), __print(i); std::cerr << "}";}
void _print() {std::cerr << "]\n";}
template <typename T, typename... V> void _print(T t, V... v) {__print(t); if (sizeof...(v)) std::cerr << ", "; _print(v...);}
void println() {std::cerr << ">--------------------<" << endl;}
#ifndef ONLINE_JUDGE
#define debug(x...) cerr << "[" << #x << "] = ["; _print(x)
#else
#define debug(x...)
#endif

// templates
template <class T> bool ckmin(T &a, const T &b) {return b<a ? a = b, 1 : 0;}
template <class T> bool ckmax(T &a, const T &b) {return b>a ? a = b, 1 : 0;}
template <class T> using gr = greater<T>;
template <class T> using vc = vector<T>;
template <class T> using p_q = priority_queue<T>;
template <class T> using pqg = priority_queue<T, vc<T>, gr<T>>;
template <class T1, class T2> using pr = pair<T1, T2>;
mt19937_64 rng_ll(chrono::steady_clock::now().time_since_epoch().count());
int rng(int M) {return (int)(rng_ll()%M);} /*returns any random number in [0, M) */

// const variables
constexpr int INF = (int)2e9;
constexpr int MOD = 998244353;
constexpr ll LL_INF = (ll)3e18;
constexpr int mod = (int)1e9 + 7;
constexpr ll inverse = 500000004LL; // inverse of 2 modulo 1e9 + 7

void setIO(const string& str) {// fast input/output
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    if (str.empty()) return;
    freopen((str + ".in").c_str(), "r", stdin);
    freopen((str + ".out").c_str(), "w", stdout);
}

int N;
vi x;
vc<vi> adj;
vi dp1, dp2, up, p;

void dfs(int v, int par) {
    p[v] = par;
    pqg<int> pq;
    int sum = 0;
    fch(u, adj[v]) if (u != par) {
        if (x[u] == 1) up[u] = up[v] + 1;
        dfs(u, v);
        pq.push(dp1[v]);
        if (x[v] == 1) {
            ckmax(dp1[v], dp1[u] + 1);
        }
        sum += dp1[v];
        while (sz(pq) > 2) {
            sum -= pq.top();
            pq.pop();
        }
    }
    if (x[v] == 2) {
        ckmax(dp2[v], sum + 1);
    }
}

void upd(pll& pp, pll q) {
    if ((ll)pp.ff * q.ss > (ll)q.ff * pp.ss) {
        pp = q;
    }
}

signed main() { // TIME YOURSELF !!!
    setIO("");
    cin >> N;
    adj.rsz(N+1);
    for (int i = 0; i < N-1; ++i) {
        int a, b;
        cin >> a >> b;
        adj[a].PB(b);
        adj[b].PB(a);
    }
    x.rsz(N+1), dp1.rsz(N+1, 0), dp2.rsz(N+1, 0), up.rsz(N+1, 0), p.rsz(N+1, -1);
    pll pq = {INF, 1}; // assume answer is 0 at first
    for (int i = 1; i <= N; ++i) {
        cin >> x[i];
        upd(pq, {x[i], 1});
        if (x[i] == 1) {
            dp1[i] = 1;
            up[i] = 1;
        } else if (x[i] == 2) {
            dp2[i] = 1;
        }
    }
    dfs(1, -1);
    for (int i = 1; i <= N; ++i) {
        if (dp1[i] != 0) upd(pq, {1, dp1[i]});
    }
    for (int i = 1; i <= N; ++i) {
        if (x[i] == 2) upd(pq, {2, dp2[i]});
        if (p[i] != -1) {
            int mx = 0;
            fch(u, adj[i]) {
                ckmax(mx, dp1[u]);
            }
            if (x[i] == 2) upd(pq, {2, mx + 1 + dp1[p[i]]});
        }
    }
    for (int i = 1; i <= N; ++i) {
        int sum = 0;
        pqg<int> pg;
        fch(u, adj[i]) if (u != p[i]) {
            sum += dp1[u];
            pg.push(dp1[u]);
            while (sz(pg) > 2) {
                sum -= pg.top();
                pg.pop();
            }
        }
        if (x[i] == 1) {
            upd(pq, {1, 1 + sum});
        }
    }
    cout << pq.ff << '/' << pq.ss << '\n';
    return 0;
}

// TLE -> TRY NOT USING DEFINE INT LONG LONG
// CE -> CHECK LINE 45
// 5000 * 5000 size matrices are kinda big (potential mle)
// Do something, start simpler

컴파일 시 표준 에러 (stderr) 메시지

mag.cpp: In function 'void setIO(const string&)':
mag.cpp:88:12: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   88 |     freopen((str + ".in").c_str(), "r", stdin);
      |     ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
mag.cpp:89:12: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)' declared with attribute 'warn_unused_result' [-Wunused-result]
   89 |     freopen((str + ".out").c_str(), "w", stdout);
      |     ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 12 / 12
• Subtask 2: 0 / 12
• Subtask 3: 12 / 12
• Subtask 4: 0 / 12
• Subtask 5: 0 / 12
• Subtask 6: 12 / 12
• Subtask 7: 0 / 12
• Subtask 8: 12 / 12
• Subtask 9: 12 / 12
• Subtask 10: 0 / 12