Submission #999476

#TimeUsernameProblemLanguageResultExecution timeMemory
999476yoav_sRoads (CEOI20_roads)C++17
0 / 100
1 ms604 KiB
#include <bits/stdc++.h> using namespace std; #define double long double typedef long long ll; typedef vector<ll> v; typedef vector<v> vv; typedef vector<vv> vvv; typedef pair<ll,ll> p; typedef vector<p> vp; typedef vector<vp> vvp; typedef vector<vvp> vvvp; typedef pair<ll, p> tri; typedef vector<tri> vtri; typedef vector<vtri> vvtri; typedef vector<vvtri> vvvtri; typedef vector<bool> vb; typedef vector<vb> vvb; typedef vector<vvb> vvvb; #define f first #define s second #define pb push_back #define eb emplace_back #define all(v) (v).begin(),(v).end() const ll INF = 1e18; const ll mod = 1e9 + 7; p operator+(p a, p b) { return p(a.f + b.f, a.s + b.s); } p operator-(p a, p b) { return p(a.f - b.f, a.s - b.s); } ll operator*(p a, p b) { return a.s * b.f - a.f * b.s; } const double pi = 3.14159265358979323846264338327950288419716939937510; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); ll N; cin >> N; vector<pair<p,p>> edges(N); for (ll i = 0; i < N; i++) cin >> edges[i].f.f >> edges[i].f.s >> edges[i].s.f >> edges[i].s.s; for (ll i = 0 ;i < N; i++) { edges[i] = {min(edges[i].f, edges[i].s), max(edges[i].f, edges[i].s)}; } complex<double> diff(edges[0].s.f - edges[0].f.f, edges[0].s.s - edges[0].f.s); double angle = arg(diff); vector<pair<double, double>> identifier(N); for (ll i= 0 ; i < N; i++) { complex<double> comp = complex<double>(edges[i].f.f, edges[i].f.s); comp = polar(abs(comp), arg(comp) + angle); identifier[i] = pair<double,double>(comp.imag(), comp.real()); } v perm(N); for (ll i = 0; i < N; i++) perm[i] = i; sort(all(perm), [&identifier](ll i, ll j){return identifier[i] < identifier[j];}); vector<pair<p, p>> edgesSorted; for (ll i= 0; i < N; i++) edgesSorted.pb(edges[perm[i]]); for (ll i = 0; i < (ll)edges.size() - 1; i++) { cout << edgesSorted[i].f.f << " " << edgesSorted[i].f.s << " " << edgesSorted[i + 1].f.f << " " << edgesSorted[i + 1].f.s << "\n"; } return 0; }
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