This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
#define double long double
typedef long long ll;
typedef vector<ll> v;
typedef vector<v> vv;
typedef vector<vv> vvv;
typedef pair<ll,ll> p;
typedef vector<p> vp;
typedef vector<vp> vvp;
typedef vector<vvp> vvvp;
typedef pair<ll, p> tri;
typedef vector<tri> vtri;
typedef vector<vtri> vvtri;
typedef vector<vvtri> vvvtri;
typedef vector<bool> vb;
typedef vector<vb> vvb;
typedef vector<vvb> vvvb;
#define f first
#define s second
#define pb push_back
#define eb emplace_back
#define all(v) (v).begin(),(v).end()
const ll INF = 1e18;
const ll mod = 1e9 + 7;
p operator+(p a, p b)
{
return p(a.f + b.f, a.s + b.s);
}
p operator-(p a, p b)
{
return p(a.f - b.f, a.s - b.s);
}
ll operator*(p a, p b)
{
return a.s * b.f - a.f * b.s;
}
const double pi = 3.14159265358979323846264338327950288419716939937510;
int main()
{
ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);
ll N;
cin >> N;
vector<pair<p,p>> edges(N);
for (ll i = 0; i < N; i++) cin >> edges[i].f.f >> edges[i].f.s >> edges[i].s.f >> edges[i].s.s;
for (ll i = 0 ;i < N; i++)
{
edges[i] = {min(edges[i].f, edges[i].s), max(edges[i].f, edges[i].s)};
}
complex<double> diff(edges[0].s.f - edges[0].f.f, edges[0].s.s - edges[0].f.s);
double angle = arg(diff);
vector<pair<double, double>> identifier(N);
for (ll i= 0 ; i < N; i++)
{
complex<double> comp = complex<double>(edges[i].f.f, edges[i].f.s);
comp = polar(abs(comp), arg(comp) - pi / 2 + angle);
identifier[i] = {comp.real(), comp.imag()};
}
v perm(N);
for (ll i = 0; i < N; i++) perm[i] = i;
sort(all(perm), [&identifier](ll i, ll j){return identifier[i] < identifier[j];});
vector<pair<p, p>> edgesSorted;
for (ll i= 0; i < N; i++) edgesSorted.pb(edges[perm[i]]);
for (ll i = 0; i < (ll)edges.size() - 1; i++)
{
cout << edgesSorted[i].f.f << " " << edgesSorted[i].f.s << " " << edgesSorted[i + 1].f.f << " " << edgesSorted[i + 1].f.s << "\n";
}
return 0;
}
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