제출 #997274

#제출 시각아이디문제언어결과실행 시간메모리
997274biank봉쇄 시간 (IOI23_closing)C++17
21 / 100
1085 ms10068 KiB
#include <bits/stdc++.h>

using namespace std;

using ll = long long;
using ii = pair<int, int>;

const ll INF = 1e18;
const int MAX_N = 3000;

vector<ii> adj[MAX_N];

void dfs(int u, vector<ll> &dist, int p = -1, ll d = 0) {
    dist[u] = d;
    for (auto [v, w] : adj[u]) {
        if (v != p) dfs(v, dist, u, d + w);
    }
}

int max_score(int N, int X, int Y, ll K, vector<int> U, vector<int> V, vector<int> W) {
    for (int i = 0; i < N; i++) adj[i].clear(); 
    for (int i = 0; i < N - 1; i++) {
        adj[U[i]].emplace_back(V[i], W[i]);
        adj[V[i]].emplace_back(U[i], W[i]);
    }
    vector<ll> distToX(N), distToY(N);
    dfs(X, distToX), dfs(Y, distToY);
    vector<ll> val[2], pref[2];
    for (int i = 0; i < 2; i++) {
        val[i].resize(N);
        pref[i].assign(N + 1, 0);
    }
    for (int i = 0; i < N; i++) {
        tie(val[0][i], val[1][i]) = minmax(distToX[i], distToY[i]);
        val[1][i] -= val[0][i];
        for (int j = 0; j < 2; j++) {
            pref[j][i + 1] = pref[j][i] + val[j][i];
        }
    }
    int ans = 0;
    for (int i = 0; i <= X; i++) {
        for (int j = Y; j < N; j++) {
            ll sum = pref[0][j + 1] - pref[0][i];
            for (int k = X + 1; k < Y; k++) {
                int lo = k - 2, hi = Y;
                while (lo + 1 < hi) {
                    int mid = (lo + hi) / 2;
                    if (sum - pref[0][mid + 1] + pref[0][k] <= K) hi = mid;
                    else lo = mid;
                }
                if (hi != Y) {
                    ans = max(ans, (j - i + 1) - (hi - k + 1));
                }
            }
            for (int k = i; k <= j; k++) {
                int lo = k - 2, hi = j + 1;
                while (lo + 1 < hi) {
                    int mid = (lo + hi) / 2;
                    if (sum + pref[1][mid + 1] - pref[1][k] <= K) lo = mid;
                    else hi = mid; 
                }
                if (lo != k - 2) {
                    ans = max(ans, (j - i + 1) + (lo - k + 1));
                }
            }
        }
    }
    return ans;
}
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