Submission #996564

#	Time	Username	Problem	Language	Result	Execution time	Memory
996564		3lektra	Crocodile's Underground City (IOI11_crocodile)	C++14	0 / 100	1 ms	4440 KiB

crocodile

#include <bits/stdc++.h>
#include "crocodile.h"
#define vi vector<int>
#define vc vector
#define pi pair<int,int>
using namespace std;

vc<vc<pi>> edg; // Edges, aka the corridors coming out from each room
vc<pi> dis; // The two minimum distances found between 2 nodes. The fastest route will just be used to calculate the second fastest, which is the oke that will be used to obtain the other distances
int fpath = -1e9-7; // Fastest path
int u, c; // Amazing the amount of situations when a node and a cost can be useful

void dijkstra(int p[]){ // First Node
    priority_queue<pi> tv; // To Visit, not TeleVision or To Vandalize
    for(int i = 0; i < sizeof(p)/sizeof(int); i++){
        tv.push({0,p[i]});
        dis[p[i]].first = 0;}
    while(!tv.empty()){
        u = tv.top().second; // The node being explored right now
        c = tv.top().first; // The cost to get to u
        tv.pop();
        
        if(dis[u].second>c){continue;} // If this path is worse then why bother
        if(u == 0){
            fpath = max(fpath, c);
            continue;}
            
        for(pi p : edg[u]){     // p.first = cost, p.second = node the path leads to
            if (p.first + c > dis[p.second].second){    // If this is path you've found is fastest than the second fastest one...
                if (p.first + c > dis[p.second].first){     // And than the fastest one...
                    dis[p.second].second = dis[p.second].first;     // Then the previously fastest one becomes the second fastest one...
                    dis[p.second].first = p.first + c;}     // This new path becomes the fastest!
                    
                else{ // But if it's not fastest than the fastest one...
                    dis[p.second].second = p.first + c;}
                    
                tv.push({dis[p.second].second, p.second});
            

            }
        }
    }
}



int travel_plan(int N, int M, int R[][2], int L[], int K, int P[]){
    edg = vc<vc<pi>>(N);
    for(int i = 0; i < M; i++){
        edg[R[i][0]].push_back({-L[i],R[i][1]});
        edg[R[i][1]].push_back({-L[i],R[i][0]});}
    
    dis = vc<pi>(N,{-1e9-7,-1e9-7});  
        
    dijkstra(P);

    //for(pi i : dis){cout << i.first << ' ' << i.second << " -- ";}
    //cout << -fpath;
return -fpath;}

Compilation message (stderr)

crocodile.cpp: In function 'void dijkstra(int*)':
crocodile.cpp:15:31: warning: 'sizeof' on array function parameter 'p' will return size of 'int*' [-Wsizeof-array-argument]
   15 |     for(int i = 0; i < sizeof(p)/sizeof(int); i++){
      |                              ~^~
crocodile.cpp:13:19: note: declared here
   13 | void dijkstra(int p[]){ // First Node
      |               ~~~~^~~
crocodile.cpp:15:22: warning: comparison of integer expressions of different signedness: 'int' and 'long unsigned int' [-Wsign-compare]
   15 |     for(int i = 0; i < sizeof(p)/sizeof(int); i++){
      |                    ~~^~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 0 / 46
• Subtask 2: 0 / 43
• Subtask 3: 0 / 11