# | Submission time | Handle | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
996517 | 2024-06-10T18:15:26 Z | 3lektra | Crocodile's Underground City (IOI11_crocodile) | C++14 | 0 ms | 0 KB |
#include <bits/stdc++.h> #define vi vector<int> #define vc vector #define pi pair<int,int> using namespace std; vc<vc<pi>> edg; // Edges, aka the corridors coming out from each room vc<pi> dis; // The two minimum distances found between 2 nodes. The fastest route will just be used to calculate the second fastest, which is the oke that will be used to obtain the other distances int fpath = -1e9-7; // Fastest path int u, c; // Amazing the amount of situations when a node and a cost can be useful void dijkstra(vi p){ // First Node priority_queue<pi> tv; // To Visit, not TeleVision or To Vandalize for(int i : p){ tv.push({0,i}); dis[i].first = 0;} while(!tv.empty()){ u = tv.top().second; // The node being explored right now c = tv.top().first; // The cost to get to u tv.pop(); if(dis[u].second>c){continue;} // If this path is worse then why bother if(u == 0){ fpath = max(fpath, c); continue;} for(pi p : edg[u]){ // p.first = cost, p.second = node the path leads to if (p.first + c > dis[p.second].second){ // If this is path you've found is fastest than the second fastest one... if (p.first + c > dis[p.second].first){ // And than the fastest one... dis[p.second].second = dis[p.second].first; // Then the previously fastest one becomes the second fastest one... dis[p.second].first = p.first + c;} // This new path becomes the fastest! else{ // But if it's not fastest than the fastest one... dis[p.second].second = p.first + c;} tv.push({dis[p.second].second, p.second}); } } } } int travel_plan(int n, int m, int (*) 2 r, int l, int k, int p){ edg = vc<vc<pi>>(n); for(int i = 0; i < m; i++){ edg[r[i][0]].push_back({-l[i],r[i][1]}); edg[r[i][1]].push_back({-l[i],r[i][0]});} dis = vc<pi>(n,{-1e9-7,-1e9-7}); dijkstra(p); //for(pi i : dis){cout << i.first << ' ' << i.second << " -- ";} //cout << -fpath; return -fpath;} return 0;}