Submission #995645

#TimeUsernameProblemLanguageResultExecution timeMemory
995645vyshniak_nLet's Win the Election (JOI22_ho_t3)C++17
0 / 100
566 ms1048580 KiB
//#pragma optimize("Ofast") //#pragma optimize("unroll-loops") //#pragma traget("avx,avx2") #include <iostream> #include <cmath> #include <algorithm> #include <stdio.h> #include <cstdint> #include <cstring> #include <string> #include <cstdlib> #include <vector> #include <bitset> #include <map> #include <queue> #include <ctime> #include <stack> #include <set> #include <list> #include <random> #include <deque> #include <functional> #include <iomanip> #include <sstream> #include <fstream> #include <complex> #include <numeric> #include <cassert> #include <array> #include <tuple> #include <unordered_map> #include <unordered_set> #include <thread> typedef long long ll; typedef unsigned long long ull; typedef long double ld; #define el '\n' #define ff first #define ss second #define pb push_back #define pf push_front #define popb pop_back #define popf pop_front #define point pair <ll, ll> #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(), x.rend() using namespace std; #include <random> mt19937 rnd(time(0)); const ll INF = 1e18 + 10; const ll inf = 1e9 + 10; const ll N = 1e6 + 10; const ll mod = 1e9 + 7; const ll LOG = 20; const ll K = 1e3 + 20; ld dp[510][510][510]; void solve() { ll n, k; cin >> n >> k; vector <ll> a(n), b(n); for (ll i = 0; i < n; i++) { cin >> a[i] >> b[i]; if (b[i] == -1) b[i] = inf; } vector <ll> order; for (ll i = 0; i < n; i++) order.pb(i); sort(all(order), [&](const ll &i, const ll &j) -> bool { if (b[i] == b[j]) return a[i] < a[j]; return b[i] < b[j]; }); for (ll i = 0; i <= n; i++) for (ll j = 0; j <= n; j++) for (ll x = 0; x <= n; x++) dp[i][j][x] = inf; dp[0][0][1] = 0; for (ll i = 1; i <= n; i++) { for (ll j = 0; j <= k; j++) { for (ll cnt = 1; cnt <= j + 1; cnt++) { dp[i][j][cnt] = dp[i - 1][j][cnt]; if (j == 0) continue; dp[i][j][cnt] = min(dp[i][j][cnt], dp[i - 1][j - 1][cnt] + (ld)a[order[i - 1]] / (ld)cnt); if (b[order[i - 1]] != inf) dp[i][j][cnt] = min(dp[i][j][cnt], dp[i - 1][j - 1][cnt - 1] + (ld)b[order[i - 1]] / (ld)(cnt - 1)); } } } ld ans = inf; for (ll i = 0; i <= n; i++) ans = min(ans, dp[n][k][i]); cout << fixed << setprecision(5) << ans << el; return; } signed main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); int tests = 1; //cin >> tests; while (tests--) solve(); return 0; } /* */
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