This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp>
using namespace std;
//using namespace __gnu_pbds;
#define speed ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
#define russian setlocale(LC_ALL,"Russian_Russia.20866");
#define file freopen("onlyone.in", "r", stdin), freopen("onlyone.out", "w", stdout);
#define ll long long
#define ull unsigned long long
#define ld long double
#define pll pair<ll, ll>
#define pii pair<int, int>
#define all(s) s.begin(), s.end()
#define pb push_back
#define ins insert
#define mp make_pair
#define sz(x) x.size()
#define F first
#define S second
#define lb lower_bound
#define ub upper_bound
#define mem(x) memset(x, 0, sizeof(x))
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const ll N = 2010;
const ll M = 600000;
const ll block = 316;
const ll mod = 998244353;
const ll P = 263;
const ld pi = acos(-1);
const ll inf = 1e9;
ll add(ll a, ll b) {
if(a + b < 0) return a + b + mod;
if(a + b >= mod) return a + b - mod;
return a + b;
}
ll sub(ll a, ll b) {
return (a - b + mod) % mod;
}
ll mul(ll a, ll b) {
return a * 1LL * b % mod;
}
ll binpow(ll a, ll n) {
ll res = 1LL;
while(n) {
if(n & 1) res = mul(res, a); // if(n % 2 == 1)
a = mul(a, a);
n >>= 1; //n / 2
}
return res;
}
ll inv(ll x) {//число х в степени -1
return binpow(x, mod - 2);
}
ll n, a, b;
ll y[N];
bool check(ll msk) {
if(a == 1) {
ll dp[n + 1];
fill(dp, dp + n + 1, inf);
dp[0] = 0LL;
for(ll i = 0; i < n; i++) {
ll cur = 0LL;
for(ll k = i + 1; k <= n; k++) {
cur += y[k];
if((cur | msk) == msk) {
dp[k] = min(dp[k], dp[i] + 1LL);
}
}
}
return (dp[n] <= b);
}
bool dp[n + 1][b + 1];
for(ll i = 0; i <= n; i++) {
for(ll j = 0; j <= b; j++) {
dp[i][j] = false;
}
}
dp[0][0] = true;
for(ll i = 0; i < n; i++) {
for(ll j = 0; j < b; j++) {
if(dp[i][j]) {
ll cur = 0LL;
for(ll k = i + 1; k <= n; k++) {
cur += y[k];
if((cur | msk) == msk) {
dp[k][j + 1] = true;
}
}
}
}
}
for(ll i = a; i <= b; i++) {
if(dp[n][i]) {
return true;
}
}
return false;
}
void solve() {
cin >> n >> a >> b;
for(ll i = 1; i <= n; i++) cin >> y[i];
ll ans = (1LL << 41LL) - 1LL;
for(ll i = 40; i >= 0; i--) {
if(check(ans ^ (1LL << i))) {
ans ^= (1LL << i);
}
}
cout << ans << '\n';
}
signed main() {
speed;
//file;
int test = 1;
//cin >> test;
while(test--) {
solve();
}
}
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