Submission #993474

#TimeUsernameProblemLanguageResultExecution timeMemory
993474doducanhHard route (IZhO17_road)C++14
100 / 100
578 ms179028 KiB
#include <bits/stdc++.h> using namespace std; using ll = long long; int main() { int n; cin >> n; vector<vector<int>> adj(n); for (int i = 1; i < n; i++) { int x, y; cin >> x >> y; adj[--x].push_back(--y); adj[y].push_back(x); } vector<int> max_length(n); vector<int> path_count(n); /** * Calculates the longest path from vertex u, * and the number of such paths. */ function<void(int, int)> dfs = [&](int u, int p) { max_length[u] = 0; path_count[u] = 1; for (int v : adj[u]) if (v != p) { dfs(v, u); if (max_length[u] < max_length[v] + 1) { max_length[u] = max_length[v] + 1; path_count[u] = path_count[v]; } else if (max_length[v] + 1 == max_length[u]) { path_count[u] += path_count[v]; } } }; dfs(0, -1); ll max_hardness = 0; ll hardest_path_count = 1; /** * Performs the rerooting, to count the hardest * path and the # of such paths at this vertex. */ function<void(int, int, ll, ll)> dfs2 = [&](int u, int p, ll parent_dist, ll parent_count) { vector<array<ll, 2>> paths; // {distance, count} if (u > 0 || (int)adj[u].size() == 1) { paths.push_back({parent_dist, parent_count}); } for (int v : adj[u]) if (v != p) { paths.push_back({max_length[v] + 1, path_count[v]}); } sort(paths.begin(), paths.end(), greater<>()); if ((int)adj[u].size() >= 3) { // can form a nonzero hardness route /* * Let the 3 longest path lengths be a, b, c, with a > b > c. * The optimal hard route "hardness" is a * (b + c). */ ll a = paths[0][0]; ll b = paths[1][0]; ll c = paths[2][0]; ll current_hardness = a * (b + c); ll current_path_count = 0; ll ties = 0; for (auto [len, amt] : paths) { if (len == c) { ties += amt; } } if (a != b && b != c) { // case 1: all are distinct. current_path_count = paths[0][1]*paths[1][1] * ties; } else if (a == b && b == c) { // case 2: all are the same. current_path_count = ties * ties; for (auto [len, amt] : paths) { if (len == a) { current_path_count -= amt * amt; } } current_path_count /= 2; // avoiding double counting } else if (a == b) { // case 3: first two are the same. current_path_count = (paths[0][1] + paths[1][1]) * ties; } else { // case 4: last two are the same. current_path_count = ties * ties; for (auto [len, amt] : paths) { if (len == c) { current_path_count -= amt * amt; } } current_path_count /= 2; // avoiding double counting } if (max_hardness < current_hardness) { max_hardness = current_hardness; hardest_path_count = current_path_count; } else if (max_hardness == current_hardness) { hardest_path_count += current_path_count; } } // processing parent dist and parent count. ll longest1 = 0; ll longest2 = 0; ll count1 = 0; ll count2 = 0; for (auto [len, amt] : paths) { if (len + 1 > longest1) { swap(longest1, longest2); swap(count1, count2); longest1 = len + 1; count1 = amt; } else if (len + 1 == longest1) { count1 += amt; } else if (len + 1 > longest2) { longest2 = len + 1; count2 = amt; } else if (len + 1 == longest2) { count2 += amt; } } for (int v : adj[u]) if (v != p) { // using the best parent hardness and parent count possible. if (max_length[v] + 2 == longest1) { (path_count[v] == count1) ? dfs2(v, u, longest2, count2) : dfs2(v, u, longest1, count1 - path_count[v]); } else { dfs2(v, u, longest1, count1); } } }; dfs2(0, -1, 0, 1); cout << max_hardness << ' ' << hardest_path_count << '\n'; }

Compilation message (stderr)

road.cpp: In lambda function:
road.cpp:67:14: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17'
   67 |    for (auto [len, amt] : paths) {
      |              ^
road.cpp:77:15: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17'
   77 |     for (auto [len, amt] : paths) {
      |               ^
road.cpp:87:15: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17'
   87 |     for (auto [len, amt] : paths) {
      |               ^
road.cpp:106:13: warning: structured bindings only available with '-std=c++17' or '-std=gnu++17'
  106 |   for (auto [len, amt] : paths) {
      |             ^
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