Submission #992028

#	Time	Username	Problem	Language	Result	Execution time	Memory
992028		huutuan	Holiday (IOI14_holiday)	C++14	23 / 100	151 ms	8608 KiB

holiday

#include"holiday.h"

#include <bits/stdc++.h>

using namespace std;

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

using namespace __gnu_pbds;

#define int long long

template<class T, class U>
using ordered_set=tree<T, null_type, U, rb_tree_tag, tree_order_statistics_node_update>;

struct DS{
   int count;
   int sum;
   ordered_set<pair<int, int>, greater<pair<int, int>>> st;
   void clear(){
      count=0;
      sum=0;
      st.clear();
   }
   DS (){
      clear();
   }
   int size(){
      return st.size();
   }
   void set_count(int new_count){
      new_count=max(new_count, 0ll);
      while (count<new_count){
         if (size()>count) sum+=st.find_by_order(count)->first;
         ++count;
      }
      while (count>new_count){
         --count;
         if (size()>count) sum-=st.find_by_order(count)->first;
      }
   }
   void insert(pair<int, int> x){
      int id=st.order_of_key(x);
      if (id<count){
         sum+=x.first;
         st.insert(x);
         if (size()>count) sum-=st.find_by_order(count)->first;
      }else st.insert(x);
   }
   void erase(pair<int, int> x){
      int id=st.order_of_key(x);
      if (id<count){
         sum-=x.first;
         st.erase(x);
         if (size()>=count) sum+=st.find_by_order(count-1)->first;
      }else st.erase(x);
   }
} st;

const int N=1e5;
int a[N], n, start, d, ans;

void solve(){
   for (int l=start; l>=0; --l){
      st.set_count(d-(start-l));
      st.insert({a[l], l});
      ans=max(ans, st.sum);
   }
   st.clear();
   for (int i=0; i<start; ++i) st.insert({a[i], i});
   for (int l=0, r=start-1; l<=start; ++l){
      while (r+1<n){
         int old_val=st.sum;
         st.insert({a[r+1], r+1});
         st.set_count(d-(start-l)-(r+1-l));
         int new_val=st.sum;
         if (new_val<old_val){
            st.erase({a[r+1], r+1});
            st.set_count(d-(start-l)-(r-l));
            break;
         }
         ++r;
      }
      ans=max(ans, st.sum);
      st.erase({a[l], l});
   }
   st.clear();
}

int findMaxAttraction(int32_t _n, int32_t _start, int32_t _d, int32_t _a[]) {
   n=_n; start=_start; d=_d;
   for (int i=0; i<n; ++i) a[i]=_a[i];
   solve();
   start=n-start-1;
   reverse(a, a+n);
   solve();
   return ans;
}

• Subtask 1: 0 / 7
• Subtask 2: 23 / 23
• Subtask 3: 0 / 17
• Subtask 4: 0 / 53