Submission #991053

#TimeUsernameProblemLanguageResultExecution timeMemory
991053grtFish 3 (JOI24_fish3)C++17
27 / 100
300 ms66128 KiB
#include <bits/stdc++.h> #define ST first #define ND second #define PB push_back using namespace std; using ll = long long; using pi = pair<int, int>; using vi = vector<int>; const int nax = 300 * 1000 + 10; struct SegTree { ll T[(1 << 20)]; int R; void upd(int a, ll x) { a += R; T[a] += x; while (a > 1) { a >>= 1; T[a] += x; } } ll qr(int a, int b) { a += R; b += R; if (a > b) return 0LL; ll w = T[a] + (a != b ? T[b] : 0LL); while (a/2 != b/2) { if (a % 2 == 0) w += T[a + 1]; if (b % 2 == 1) w += T[b - 1]; a >>= 1; b >>= 1; } return w; } void init(int n) { R = 1; while (R < n) R <<= 1; for (int i = 0; i < 2 * R; ++i) T[i] = 0; } int go_down() { int v = 1; while (v < R) { if (T[2 * v + 1] != 0) v = v*2 + 1; else v = v*2; } return v - R; } }; vector<pair<int,int>>qrs[nax]; ll ans[nax]; int main() { ios_base::sync_with_stdio(0); cin.tie(0); int n, q; ll d; cin >> n >> d; vector<ll> a(n); for (ll &x : a) cin >> x; cin >> q; vector<ll> demands(n); for (int i = 1; i < n; ++i) { demands[i] = a[i] - a[i - 1]; if (demands[i] < 0) { demands[i] = (abs(demands[i]) - 1) / d + 1; } else { demands[i] = -(demands[i] / d); } } for (int l,r, i = 0; i < q; ++i) { cin >> l >> r; l--, r--; qrs[r].emplace_back(l, i); } SegTree s, lft, closed, total; s.init(n); lft.init(n); closed.init(n); total.init(n); for (int i = 1; i < n; ++i) { // update value i //cerr << "i: " << i << " " << demands[i] << "\n"; if (demands[i] < 0) { s.upd(i, -demands[i]); // I can give that many } else { lft.upd(i, demands[i] * i); total.upd(i, demands[i]); while (demands[i] > 0) { if (s.T[1] == 0) break; int v = s.go_down(); ll me = min(demands[i], s.qr(v,v)); s.upd(v, -me); closed.upd(v, me); lft.upd(v, -me * v); //cerr << "segment: " << v << "->" << i << " " << me << " times\n"; } } for (auto [l, id] : qrs[i]) { ll open = total.qr(l + 1, i) - closed.qr(l + 1, i); ll res = lft.qr(l + 1, i); ll me = a[l] / d; //cerr << "(" << total.qr(l+1,i) << " " << closed.qr(l+1, i) << ")" << " " << res << " " << me << "\n"; if (me < open) { ans[id] = -1; } else { ans[id] = res - (ll)l * open; } } } for (int i = 0; i < q; ++i) cout << ans[i] << "\n"; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...