Submission #990560

#TimeUsernameProblemLanguageResultExecution timeMemory
990560LibGame (IOI14_game)C++14
0 / 100
1 ms604 KiB
#include <bits/stdc++.h> using namespace std; int q[10003]; int con[10003]; int N; void initialize(int n){ N=n-1; } /* The key idea is simple: Build a tree and that's it. Find a way to build a tree so that, up until the penultimate query, is not yet a tree. Could be done in many ways: the DSU that only connects the final edges between 2 components, the kind of thing mentioned in the editorial, or.......find a way to seperate all kinds of edges into N-1 non-intersecting sets, then answering YES to the final edge that belongs to each individual set. Instead of following the big-brain thing of the editorial........ */ int hasEdge(int u, int v){ q[abs(u-v)]++; return (q[abs(u-v)]==N-abs(u-v)); }
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