이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
const int N=5e5+10;
int n, m, mod;
pair<int, int> a[N];
int solve(vector<pair<int, int>> v){
if (v.empty()) return 0;
int z=v.back().second;
vector<int> cnt(m+1), cnt2(m+1);
for (auto &i:v) if (i.first*2<=v.back().first) ++cnt[i.second];
int ans=accumulate(cnt.begin(), cnt.end(), 1ll, [&](int x, int y){ return x*(y+1)%mod; });
for (int i=0, j=-1; i<(int)v.size(); ++i){
while (v[j+1].first*2<=v[i].first){
++j;
++cnt2[v[j].second];
}
if (v[i].second!=z && cnt2[v[i].second]>=cnt[v[i].second]){
int prod=1;
for (int k=1; k<=m; ++k) if (k!=v[i].second) prod=prod*(cnt2[k]+1-(k==z))%mod;
ans=(ans+prod)%mod;
}
}
vector<pair<int, int>> v2;
for (auto &i:v) if (i.second!=z) v2.push_back(i);
return ans+solve(v2)%mod;
}
int32_t main(){
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
cin >> n >> m >> mod;
for (int i=1; i<=n; ++i) cin >> a[i].first >> a[i].second;
sort(a+1, a+n+1);
cout << solve(vector<pair<int, int>>(a+1, a+n+1)) << '\n';
return 0;
}
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