Submission #989099

#TimeUsernameProblemLanguageResultExecution timeMemory
989099armashkaBigger segments (IZhO19_segments)C++17
100 / 100
80 ms20864 KiB
#include<bits/stdc++.h> #pragma GCC target("avx2") #pragma GCC optimize("Ofast") #pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native") using namespace std; #define fast ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0); #define file(s) freopen(s".in", "r", stdin);freopen(s".out", "w", stdout); #define all(v) v.begin(),v.end() #define rall(v) v.rbegin(),v.rend() #define pb push_back #define pf push_front #define ppb pop_back #define ft first #define sd second #define ll long long #define pii pair<int,int> #define pll pair<ll,ll> const int N = 5e5 + 10; const int M = 2e7 + 5; const int B = 316; const ll msize = 2; const ll mod1 = 1e9 + 7; const ll mod2 = 998244353; const long double Phi = acos(-1); const long long inf = 2e18; const vector <pair<int, int>> dir = {{-1, 0}, {1, 0}, {0, -1}, {0, 1}}; ll binmul(ll x, ll ti, ll m); ll binpow(ll x, ll ti, ll m); ll n, a[N], pref[N]; pair <ll, ll> dp[N]; const void solve() { cin >> n; for (int i = 1; i <= n; ++ i) cin >> a[i], pref[i] = pref[i - 1] + a[i]; for (int i = 1; i <= n; ++ i) { dp[i] = {1, 1}; } for (int i = 1; i <= n; ++ i) { dp[i] = max(dp[i], dp[i - 1]); int cnt = dp[i].ft, j = dp[i].sd; int l = i + 1, r = n, k = -1; while (l <= r) { int mid = (l + r) / 2; if (pref[mid] - pref[i] >= pref[i] - pref[j - 1]) r = mid - 1, k = mid; else l = mid + 1; } if (k != -1) { dp[k] = max(dp[k], {cnt + 1, i + 1}); } } cout << dp[n].ft; } int main() { ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0); srand(time(NULL)); // file("maze"); // freopen("input.txt", "r", stdin); // freopen("output.txt", "w", stdout); int tt = 1; // cin >> tt; for (int i = 1; i <= tt; ++ i) { solve(); } #ifndef ONLINE_JUDGE cerr << "\n" << 1.0 * clock() / CLOCKS_PER_SEC << " s.\n"; #endif return 0; } // Template functions ll binmul(ll x, ll ti, ll m) { ll res = 0;while (ti){if(ti & 1)res += x;x += x;ti >>= 1; x %= m; res %= m;} return res;} ll binpow(ll x, ll ti, ll m) { ll res = 1;while (ti){if(ti & 1)(res *= x)%=m;(x*=x)%=m;ti >>= 1; x %= m; res %= m;} return res;}
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