This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include<bits/stdc++.h>
#pragma GCC target("avx2")
#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
using namespace std;
#define fast ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define file(s) freopen(s".in", "r", stdin);freopen(s".out", "w", stdout);
#define all(v) v.begin(),v.end()
#define rall(v) v.rbegin(),v.rend()
#define pb push_back
#define pf push_front
#define ppb pop_back
#define ft first
#define sd second
#define ll long long
#define pii pair<int,int>
#define pll pair<ll,ll>
const int N = 5e5 + 10;
const int M = 2e7 + 5;
const int B = 316;
const ll msize = 2;
const ll mod1 = 1e9 + 7;
const ll mod2 = 998244353;
const long double Phi = acos(-1);
const long long inf = 2e18;
const vector <pair<int, int>> dir = {{-1, 0}, {1, 0}, {0, -1}, {0, 1}};
ll binmul(ll x, ll ti, ll m);
ll binpow(ll x, ll ti, ll m);
ll n, a[N], pref[N];
pair <ll, ll> dp[N];
const void solve() {
cin >> n;
for (int i = 1; i <= n; ++ i) cin >> a[i], pref[i] = pref[i - 1] + a[i];
for (int i = 1; i <= n; ++ i) {
dp[i] = {1, 1};
}
for (int i = 1; i < n; ++ i) {
dp[i] = max(dp[i], dp[i - 1]);
int cnt = dp[i].ft, j = dp[i].sd;
int l = i + 1, r = n, k = -1;
while (l <= r) {
int mid = (l + r) / 2;
if (pref[mid] - pref[i] >= pref[i] - pref[j - 1]) r = mid - 1, k = mid;
else l = mid + 1;
}
if (k != -1) {
dp[k] = max(dp[k], {cnt + 1, i + 1});
}
}
cout << dp[n].ft;
}
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
srand(time(NULL));
// file("maze");
// freopen("input.txt", "r", stdin);
// freopen("output.txt", "w", stdout);
int tt = 1;
// cin >> tt;
for (int i = 1; i <= tt; ++ i) {
solve();
}
#ifndef ONLINE_JUDGE
cerr << "\n" << 1.0 * clock() / CLOCKS_PER_SEC << " s.\n";
#endif
return 0;
}
// Template functions
ll binmul(ll x, ll ti, ll m) { ll res = 0;while (ti){if(ti & 1)res += x;x += x;ti >>= 1; x %= m; res %= m;} return res;}
ll binpow(ll x, ll ti, ll m) { ll res = 1;while (ti){if(ti & 1)(res *= x)%=m;(x*=x)%=m;ti >>= 1; x %= m; res %= m;} return res;}
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