Submission #987078

#	Time	Username	Problem	Language	Result	Execution time	Memory
987078		Essa2006	Fish (IOI08_fish)	C++14	9 / 100	733 ms	20820 KiB

fish

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define endl '\n'
#define FF first
#define SS second
#define all(a) a.begin(), a.end()

const int N = 1 << 20;
int n, o, mod;

vector<int> S(2 * N, 1);

int add(int a, int b) {
    return (a + b) % mod;
}

int mul(int a, int b) {
    a %= mod, b %= mod;
    return (ll)a * b % mod;
}

void update(int id, int c) {
    id += N;
    S[id] += c;
    while (id /= 2) {
        S[id] = mul(S[id * 2], S[id * 2 + 1]);
    }
}

int main() {
    ios_base::sync_with_stdio(0);cin.tie(0);

    cin >> n >> o >> mod;

    vector<array<int, 2>> A(n);
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < 2; j++) {
            cin >> A[i][j];
        }
    }

    sort(all(A));
    int r = -1;
    while (r + 1 < n && ((2 * A[r + 1][0]) <= A.back()[0])) {
        r++;
        update(A[r][1], 1);
    }

    vector<int> Frq(n + 1);
    for (int i = 0; i <= n; i++) {
        Frq[i] = S[i + N] - 1;
    }

    vector<int> Last(n + 1, n);
    int ans = 0;
    for (int i = n - 1; i >= 0; i--) {
        int k = A[i][1];
        if (Last[k] == n) {
            Last[k] = i;
            while (r >= 0 && ((2 * A[r][0]) > A[i][0])) {
                update(A[r][1], -1);
                r--;
            }
            for (int f = S[k + N]; f > 0; f--) {
                if (i == n - 1 || f - 1 == Frq[k]) {
                    int c = S[k + N];
                    update(k, -(c - 1));
                    ans = add(ans, S[1]);
                    update(k, (c - 1));
                }
            }
        }
    }

    while (r + 1 < n && ((2 * A[r + 1][0]) <= A.back()[0])) {
        r++;
        update(A[r][1], 1);
    }

    for (int i = n - 1; i >= 0; i--) {
        int k = A[i][1];
        if (Last[k] == i) {
            while (r >= 0 && ((2 * A[r][0]) > A[i][0])) {
                if (S[A[r][1] + N] != 1)
                    update(A[r][1], -1);
                r--;
            }

            int b = S[k + N];
            update(k, -(S[k + N] - 1));
            if (i == n - 1) {
                continue;
            }
            for (int f = b; f > 0; f--) {
                if (f - 1 != Frq[k]) {
                    ans = add(ans, S[1]);
                }
            }
        }
    }

    cout << ans;
}

• Subtask 1: 4 / 4
• Subtask 2: 0 / 4
• Subtask 3: 0 / 4
• Subtask 4: 0 / 4
• Subtask 5: 0 / 4
• Subtask 6: 0 / 5
• Subtask 7: 0 / 6
• Subtask 8: 0 / 6
• Subtask 9: 0 / 6
• Subtask 10: 0 / 6
• Subtask 11: 0 / 7
• Subtask 12: 0 / 7
• Subtask 13: 0 / 7
• Subtask 14: 0 / 5
• Subtask 15: 0 / 5
• Subtask 16: 5 / 5
• Subtask 17: 0 / 5
• Subtask 18: 0 / 5
• Subtask 19: 0 / 5