제출 #986639

#제출 시각아이디문제언어결과실행 시간메모리
986639CSQ31사이버랜드 (APIO23_cyberland)C++17
8 / 100
3087 ms113052 KiB
#include "cyberland.h"
#include<bits/stdc++.h>
using namespace std;

typedef long double ld;
ld dist[31][111111];
ld pw[31];
struct node{
    int v,k;
    ld dist = 0;
    node(int _k,int _v,ld _dist = 0){
        v = _v;
        k = _k;
        dist = _dist;
    }
};

struct comp
{
    bool operator() (node const &a, node const &b) { return b.dist - a.dist > 1e-10; }
};
vector<pair<int,int>>adj[111111];
double solve(int n, int m,int K, int H, vector<int> x, vector<int> y, vector<int> c, vector<int> arr){
    priority_queue<node,vector<node>,comp>pq;
    for(int j=0;j<n;j++){
        adj[j].clear();
        for(int i=0;i<=30;i++){
            dist[i][j] = 1e15;
        }
    }
    pw[0] = 1;
    for(int i=1;i<=30;i++)pw[i] = pw[i-1]*2;
    for(int i=0;i<m;i++){
        adj[x[i]].push_back({y[i],c[i]});
        adj[y[i]].push_back({x[i],c[i]});
    }

    for(int i=0;i<=K;i++){
        dist[i][H] = 0;
        pq.push(node(i,H));
    }
    while(!pq.empty()){
        node tmp = pq.top();
        int v = tmp.v;
        int k = tmp.k;
        pq.pop();
        if(abs(tmp.dist - dist[k][v]) > 1e-10)continue;
        if(arr[v] == 0)continue;

        for(pair<int,int>x : adj[v]){
            int u = x.first;
            ld w = x.second;
            if(u == H)continue;
            w /= pw[k];
            if(dist[k][u] - dist[k][v] - w > 1e-10){
                dist[k][u] = dist[k][v] + w;
                pq.push(node(k,u,dist[k][u]));
            }
            if(arr[u] == 2 && k-1 >= 0 ){
                if(dist[k-1][u] - dist[k][v] - w > 1e-10){
                    dist[k-1][u] = dist[k][v] + w;
                    pq.push(node(k-1,u,dist[k-1][u]));
                }

            }
        }
    }
    ld ans = dist[0][0];
    queue<int>q;
    vector<int>vis(n,0);
    q.push(0);
    vis[0] = 1;
    while(!q.empty()){
        int v = q.front();
        q.pop();
        if(arr[v] == 0)ans = min(ans,dist[0][v]);
        for(pair<int,int>x:adj[v]){
            int u = x.first;
            if(!vis[u]){
                q.push(u);
                vis[u] = 1;
            }
        }
    }
    if(!vis[H])return -1;
    return ans;
}
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