Submission #985526

#	Time	Username	Problem	Language	Result	Execution time	Memory
985526		Alex0x0	Stations (IOI20_stations)	C++14	0 / 100	618 ms	684 KiB

stations

// #pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math")
// #pragma GCC target("avx,avx2,fma")
#include <bits/stdc++.h>
#define f first
#define s second
#define fore(i,a,b) for(int i = (a), ThxMK = (b); i < ThxMK; ++i)
#define pb push_back
#define all(s) begin(s), end(s)
#define _ ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define sz(s) int(s.size())
#define ENDL '\n'
using namespace std;
typedef long double ld;
typedef int lli;
typedef pair<lli,lli> ii;
typedef vector<lli> vi;
typedef vector<ii> vii;
#define deb(x) cout << #x": " << (x) << endl;

const lli INF = 1e9 + 12;
const lli N = 1e3 + 12;

vector <vi> adj;

vi tk;
lli curVis = 0;
lli titi = 0;
lli vis[N];

lli dfs(lli u, lli dpth){
  // cout << u << ' ';
  vis[u] = curVis;
  if (dpth % 2 == 1) tk[u] = titi++;
  for (auto & i : adj[u]){
    if (vis[i] == curVis) continue;
    dfs(i, dpth+1);
  }
  if (dpth % 2 == 0) tk[u] = ++titi;
  return tk[u];
}

vi label(lli n, lli k, vi u, vi v){
  adj.resize(n + 5);
  for (auto &i : adj) i.clear();
  tk.resize(n);
  for (auto &i : tk) i = -1ll;
  titi = 0;
  fore(i,0,n-1){
    adj[u[i]].pb(v[i]);
    adj[v[i]].pb(u[i]);
  }
  ++curVis;
  dfs(0, 0);
  // cout << ENDL;
  return tk;
}


lli find_next_station(lli s, lli t, vi c){
  sort(all(c));
  bool minor = true;
  for (auto & i : c) if (i > s) minor = false;
  if (minor){
    fore(i,0,sz(c)-1) if (s <= t && t <= c[i]) return c[i];
    return c[sz(c)-1];
  }
  else{
    fore(i,1,sz(c)){
      lli xx = s;
      if ((i + 1) < sz(c)) xx = c[i + 1];
      if (c[i] <= t && t <= xx) return c[i];
    }
    return c[0];
  }
  return c[sz(c)-1];
}

// int main(){ _
//   // freopen("file.in","r",stdin);
//   // freopen("file.out","w",stdout);
//   vector<vi> vv;
//   lli t; cin >> t;
//   while (t--){
//     lli n, k; cin >> n >> k;
//     vi a(n-1); vi b(n-1);
//     fore(i,0,n-1) cin >> a[i] >> b[i];
//     vi v = label(n, k, a, b);
//     for (auto & i : v) cout << i << ' '; cout << ENDL;
//     vv.pb(v);
//   }
//   return 0;
// }

• Subtask 1: 0 / 5
• Subtask 2: 0 / 8
• Subtask 3: 0 / 16
• Subtask 4: 0 / 10
• Subtask 5: 0 / 61