Submission #983045

#	Time	Username	Problem	Language	Result	Execution time	Memory
983045		Faisal_Saqib	Game (APIO22_game)	C++17	30 / 100	4038 ms	6836 KiB

game

#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define pb push_back
#define vll vector<ll>
int n,k;
const int N=3e4+10;
vector<int> adj[N];
void init(int Q, int P)
{
    n=Q;
    k=P;
    for(int i=0;(i+1)<k;i++)
        adj[i].push_back(i+1);
}
bool cycle=0;
vector<int> path;
int vis[N];
bool have[N];
int cur=1;
void dfs(int x,int p=-1)
{
    path.push_back(x);
    have[x]=1;
    vis[x]=cur;
    for(auto y:adj[x])
    {
        if(vis[y]==0) // Never visited in any other dfs
        {
            dfs(y,x);
            if(cycle)
                return;
        }
        else if(vis[y]==cur and have[y]){ // Visited in this dfs but cycle is not guranteed
        
            vll ex={y};
            while(path.back()!=y)
            {
                ex.pb(path.back());
                path.pop_back();
            }
            if(path.size()==0)
            {
                exit(-10);
            }
            for(auto lp:ex)
            {
                if(lp<k)
                {
                    cycle=1;
                    return;
                }
            }
            while(ex.size())
            {
                path.pb(ex.back());
                ex.pop_back();
            }
        }
        else{// Visited in other dfs but it will not make a cycle
        // bcz if it would there would be a path from there to current node but if a path existed then we would have visited this vertex in the same dfs

        }
    }
    path.pop_back();
    have[x]=0;
}
int add_teleporter(int u, int v)
{
    adj[u].push_back(v);
    memset(vis,0,sizeof(vis));
    cur=1;
    for(int sp=0;sp<k;sp++)
    {
        if(!vis[sp])
        {
            path.clear();
            cycle=0;
            dfs(sp);
            if(cycle)
            {
                return 1;
            }
            cur++;
        }
    }    
    return 0;
}

• Subtask 1: 2 / 2
• Subtask 2: 10 / 10
• Subtask 3: 18 / 18
• Subtask 4: 0 / 30
• Subtask 5: 0 / 40