This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
ll pref[100001]={0};
ll dp[100001][202]={0};
ll p[100001][202]={0};
struct line{
ll m,c;
line(ll _m, ll _c){m=_m;c=_c;}
ll intersect(line l){
return m-l.m==0 ? LLONG_MAX/4 : (l.c-c)/(m-l.m);
}
ll value(ll x){
return m*x+c;
}
};
deque<pair<line,ll>> q;
deque<ll> pos;
void insert(ll m, ll c){
line l(m,c);
while(!q.empty()&&q.front().second>=l.intersect(q.front().first)){
// cout << "irem" << ' ' << q.front().first.m << ' ' << q.front().first.c << ' ' << q.front().second << '\n';
q.pop_front();
pos.pop_front();
}
if(q.empty()){
q.push_front({l,0});
}else{
q.push_front({l,l.intersect(q.front().first)});
}
// cout << "iadd" << ' ' << q.front().first.m << ' ' << q.front().first.c << ' ' << q.front().second << '\n';
}
ll query(ll x){
while(q.size()>1&&q[q.size()-2].second<=x){
// cout << "qrem" << ' ' << q.back().first.m << ' ' << q.back().first.c << ' ' << q.back().second << '\n';
q.pop_back();
pos.pop_back();
}
// cout << "query" << ' ' << q.back().first.m << ' ' << q.back().first.c << ' ' << q.back().second << ' ' << q.back().first.value(x) <<'\n';
return q.back().first.value(x);
}
int main(){
cin.tie(0)->sync_with_stdio(0);
ll n,k; cin >> n >> k;
vector<ll> a(n);
for(ll i=0;i<n;i++)cin >> a[i];
for(ll i=0;i<n;i++)pref[i+1]=pref[i]+a[i];
for(ll j=1;j<=k+1;j++){
// q.clear();
// pos.clear();
// insert(0,0);
// pos.push_front(0);
for(ll i=1;i<=n;i++){
for(int x=0;x<i;x++){
if(dp[x][j-1]+(pref[i]-pref[x])*(pref[n]-pref[i])>=dp[i][j]){
dp[i][j]=dp[x][j-1]+(pref[i]-pref[x])*(pref[n]-pref[i]);
p[i][j]=x;
}
}
// dp[i][j]=query(pref[i]);
// p[i][j]=pos.back();
// insert(pref[i],dp[i][j-1]-pref[i]*pref[i]);
// pos.push_front(i);
// cout << '(' << i << j <<')' <<dp[i][j] << ' ' << p[i][j] << ' ';
}
// cout << '\n';
}
cout << dp[n][++k] << '\n';
ll sus=n;
vector<ll> ans;
while(p[sus][k]>0){
ans.push_back(p[sus][k--]);
sus=p[sus][k];
}
for(ll i=ans.size()-1;i>=0;i--)cout << ans[i] << ' ';
return 0;
// 7 3
// 4 1 3 4 0 2 3
// (11)0 (21)4 (31)16 (41)35 (51)35 (61)48 (71)72
// (12)0 (22)4 (32)19 (42)48 (52)48 (62)64 (72)95
// (13)0 (23)4 (33)19 (43)51 (53)51 (63)72 (73)108
// 108
}
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