# |
Submission time |
Handle |
Problem |
Language |
Result |
Execution time |
Memory |
979090 |
2024-05-10T08:29:26 Z |
Br3ad |
Toll (APIO13_toll) |
C++17 |
|
0 ms |
344 KB |
#include <iostream>
#include <fstream>
#include <iomanip>
#include <algorithm>
#include <functional>
#include <numeric>
#include <cstring>
#include <string>
#include <cmath>
#include <vector>
#include <queue>
#include <stack>
#include <set>
#include <map>
using namespace std;
#define ll long long
#define ull unsigned long long
#define f first
#define s second
#define PF push_front
#define PB push_back
#define MP make_pair
#define max(a, b) ((a > b)? a : b)
#define min(a, b) ((a < b)? a : b)
#define max3(a, b, c) max(max(a, b), c)
#define min3(a, b, c) min(min(a, b), c)
const int N = 1e5 + 5;
const int M = 1e9 + 7;
const int inf = 0x3f3f3f3f;
const ll int INF = 1e18;
struct DSU {
vector<int> parent;
DSU(int n){
parent = vector<int>(n+1);
iota(parent.begin(), parent.end(), 0);
}
int find_parent(int p){
return (parent[p] == p)? p : parent[p] = find_parent(parent[p]);
}
bool merge(int a, int b){
a = find_parent(a);
b = find_parent(b);
parent[a] = b;
return (a != b);
}
};
struct TREE {
map<pair<int, int>, bool> isPath;
vector<vector<pair<int, int>>> tree_adj;
vector<int> parent, sz;
ll total = 0, limit = 0;
TREE(int n, vector<int> &people){
tree_adj = vector<vector<pair<int, int>>>(n+1);
parent = vector<int>(n+1);
iota(parent.begin(), parent.end(), 0);
sz = people;
}
void dfs(int cur, int prev, vector<vector<pair<int, int>>> &adj){
for(auto [child, cost] : tree_adj[cur]){
if(child == prev) continue;
dfs(child, cur, adj);
if(cost == 0){
// edge (cur, child) is one of the new roads
int new_cost = find_min(child, adj);
total += 1ll * new_cost * sz[child];
}
sz[cur] += sz[child];
}
}
int find_min(int cur, vector<vector<pair<int, int>>> &adj){
int mn = inf;
for(auto [neighbour, weight] : adj[cur]){
pair<int, int> cur_edge = MP(min(cur, neighbour), max(cur, neighbour));
if(isPath[cur_edge]) continue;
mn = min(mn, weight);
}
return mn;
}
};
int main(){
ios::sync_with_stdio(false);
cin.tie(NULL);
// ifstream cin();
// ofstream cout();
int n, m, k;
cin >> n >> m >> k;
vector<vector<pair<int, int>>> adj(n+1, vector<pair<int, int>>());
vector<pair<int, pair<int, int>>> edge;
for(int i = 0; i < m; i++){
int a, b, w;
cin >> a >> b >> w;
adj[a].PB(MP(b, w));
adj[b].PB(MP(a, w));
edge.PB(MP(w, MP(a, b)));
}
for(int i = 0; i < k; i++){
int a, b;
cin >> a >> b;
adj[a].PB(MP(b, 0));
adj[b].PB(MP(a, 0));
edge.PB(MP(0, MP(a, b)));
}
vector<int> people(n+1);
for(int i = 1; i <= n; i++) cin >> people[i];
// Create minimum spanning tree which new roads are included
sort(edge.begin(), edge.end());
DSU dsu(n);
TREE tree(n, people);
for(auto [w, p] : edge){
if(dsu.merge(p.f, p.s)){
tree.tree_adj[p.f].PB(MP(p.s, w));
tree.tree_adj[p.s].PB(MP(p.f, w));
pair<int, int> cur_edge = MP(min(p.f, p.s), max(p.f, p.s));
tree.isPath[cur_edge] = true;
tree.limit = max(tree.limit, w);
}
}
// Traverse tree to calculate road passers and maximum toll fees for new roads
tree.dfs(1, -1, adj);
cout << tree.total << endl;
}
/*
5 5 1
3 5 2
1 2 3
2 3 5
2 4 4
4 3 6
1 3
10 20 30 40 50
*/
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Incorrect |
0 ms |
344 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Incorrect |
0 ms |
344 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Incorrect |
0 ms |
344 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Incorrect |
0 ms |
344 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |
# |
Verdict |
Execution time |
Memory |
Grader output |
1 |
Incorrect |
0 ms |
344 KB |
Output isn't correct |
2 |
Halted |
0 ms |
0 KB |
- |