Submission #976405

#	Time	Username	Problem	Language	Result	Execution time	Memory
976405		stefanopulos	Nestabilnost (COI23_nestabilnost)	C++17	41 / 100	171 ms	197716 KiB

code1

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <bits/stdc++.h>
 
using namespace std;
using namespace __gnu_pbds;
 
typedef long long ll;
typedef long double ldb;
 
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef pair<ldb,ldb> pdd;

#define ff(i,a,b) for(int i = a; i <= b; i++)
#define fb(i,b,a) for(int i = b; i >= a; i--)
#define trav(a,x) for(auto& a : x)
 
#define sz(a) (int)(a).size()
#define fi first
#define se second
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
 
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

template<typename T>
using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

// os.order_of_key(k) the number of elements in the os less than k
// *os.find_by_order(k)  print the k-th smallest number in os(0-based)

const int mod = 1000000007;
const ll inf = 1e15 + 5;
const int mxN = 5005; 

int n;
int A[mxN];
int f[mxN];

vector<int> g[mxN];

ll mn[mxN];
int k1[mxN];
int k2[mxN];
ll dp[mxN][mxN];
void dfs(int v, int p){

    vector<int> deca;
    for(auto u : g[v]){
        if(u != p){
            dfs(u, v);
            deca.pb(u);
        }
    }

    for(auto u : deca){
        k1[u] = k2[u] = n + 1;
        if(A[v] + 1 == A[u]){
            k1[u] = A[u] + 1; 
        }

        if(A[u] == 0){
            k2[u] = A[v] + 1;
        }
    }

    ff(i,A[v] + 1,n){

        ll kol = 0;
        for(auto u : deca){

            if(k1[u] <= i || k2[u] == i){
                kol += min(mn[u], dp[u][i] - f[i]);
            }
            else{
                kol += mn[u];
            }

        }

        dp[v][i] = min(dp[v][i], kol + f[i]);

    }

    mn[v] = inf;
    ff(i,1,n)mn[v] = min(mn[v], dp[v][i]);

}

int main(){
    cin.tie(0)->sync_with_stdio(0);

    cin >> n;
    ff(i,1,n)cin >> A[i];
    ff(i,1,n)cin >> f[i];
    ff(i,1,n - 1){
        int u, v;
        cin >> u >> v;
        g[u].pb(v);
        g[v].pb(u);
    }

    ff(i,1,n)ff(j,1,n)dp[i][j] = inf;

    dfs(1, -1);

    ll rez = inf;
    ff(i,1,n)rez = min(rez, dp[1][i]);
    cout << rez << '\n';

    return 0;
}
/*

7
2 3 0 3 2 0 0
6 8 2 9 9 9 9
1 2
2 3
1 4
4 5
5 6
5 7

// probati bojenje sahovski
*/
 
 
 
 
 

• Subtask 1: 12 / 12
• Subtask 2: 0 / 20
• Subtask 3: 7 / 7
• Subtask 4: 22 / 22
• Subtask 5: 0 / 39