Submission #974147

#	TimeUTC-0	Username	Problem	Language	Result	Execution time	Memory
974147	2024-05-02 23:30:09	nextgenxing	The Xana coup (BOI21_xanadu)	C++14	100 / 100	49 ms	25948 KiB

xanadu

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#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
#define ff first
#define ss second
#define all(x) begin(x), end(x)
#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define F0R(i, x) FOR(i, 0, x)
#define FORd(i, a, b) for(int i = (b)-1; i >= (a); i--)
#define F0Rd(i, x) FORd(i, 0, x)
#define ckif(a, b, c) ((c) ? (a) : (b))
const int MAX_N = 2e5+69;
const ll INF = 0x3f3f3f3f;
int n;
vector<int> adj[MAX_N];
int dp[MAX_N][2][2], a[MAX_N]; // what it is, whether it has toggled
void solve(int curr, int par = -1){
    int dp2[2][2] = {0}; // what the it is, what all the children are
    dp2[a[curr]^1][0] = INF, dp2[a[curr]^1][1] = INF;
    for(auto x : adj[curr]){
        if(x == par) continue;
        solve(x, curr);
        F0R(i1, 2) F0R(i2, 2) F0R(j1, 2) F0R(j2, 2) if(dp2[i1][i2] < INF && dp[x][j1][j2] < INF && i2 == j1)
            dp[curr][i1^j2][i2] = min(dp[curr][i1^j2][i2], dp2[i1][i2]+dp[x][j1][j2]);
        F0R(i, 2) F0R(j, 2) dp2[i][j] = dp[curr][i][j], dp[curr][i][j] = INF;
 
 
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• Subtask 1: 5 / 5
• Subtask 2: 15 / 15
• Subtask 3: 10 / 10
• Subtask 4: 40 / 40
• Subtask 5: 30 / 30