Submission #973396

#TimeUsernameProblemLanguageResultExecution timeMemory
973396avighnaSplit the sequence (APIO14_sequence)C++17
71 / 100
444 ms131072 KiB
#include <bits/stdc++.h> typedef long long ll; template <typename T> class Vector : public std::vector<T> { public: using std::vector<T>::vector; std::vector<ll> psum; void calculate_prefix_sum() { psum.resize(this->size()); std::partial_sum(this->begin(), this->end(), psum.begin()); } T sum(ll a, ll b) { if (a > b) { return 0; } T ans = psum[b]; if (a - 1 >= 0) { ans -= psum[a - 1]; } return ans; } }; const ll N = 1e5 + 1, K = 201; const ll inf = 1e15; ll dp[K][N]; struct Line { int m; ll b; ll eval(ll x) { return m * x + b; } }; class CHT { private: bool parallel(const Line &a, const Line &b) { return a.m == b.m; } long double x_intersection(const Line &a, const Line &b) { return (a.b - b.b) / ((long double) (b.m - a.m)); } public: std::deque<Line> dq; void insert(Line l) { if (dq.size() >= 1 && parallel(l, dq.back()) && l.b <= dq.back().b) { return; } while (dq.size() >= 2) { if (parallel(l, dq.back())) { if (l.b > dq.front().b) { dq.pop_front(); continue; } else { return; } } if (x_intersection(l, dq.back()) <= x_intersection(dq.back(), dq[dq.size() - 2])) { dq.pop_back(); } else { break; } } if (dq.size() == 1 && parallel(l, dq.back()) && l.b > dq.back().b) { dq.pop_back(); } dq.push_back(l); } ll query(ll x) { while (dq.size() >= 2 && dq[0].eval(x) <= dq[1].eval(x)) { dq.pop_front(); } return dq[0].eval(x); } }; int main() { ll n, k; std::cin >> n >> k; Vector<ll> a(n); for (auto &i : a) { std::cin >> i; } a.calculate_prefix_sum(); if (n == 2) { std::cout << a[0] * a[1] << "\n1\n"; return 0; } for (ll i = 0; i <= k; ++ i) { CHT hull; for (ll j = n - 1; j >= 0; -- j) { if (j == n - 1) { dp[i][j] = -inf * (i != 0); continue; } if (i == 0) { dp[i][j] = 0; continue; } int m = a.sum(j + 1, n - 1); ll b = dp[i - 1][j + 1] + a.sum(0, j) * a.sum(j + 1, n - 1); hull.insert({m, b}); ll ans = hull.query(-a.sum(0, j - 1)); dp[i][j] = std::max(0LL, ans); } } std::cout << dp[k][0] << "\n"; ll i = 0; ll ops = k; for (ll c = i; c < n - 1 && ops > 0; c++) { if (dp[ops][i] == a.sum(i, c) * a.sum(c + 1, n - 1) + dp[ops - 1][c + 1]) { std::cout << c + 1 << " "; ops--; i = c + 1; } } }
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