Submission #972490

#TimeUsernameProblemLanguageResultExecution timeMemory
972490stefanopulosBliskost (COI23_bliskost)C++17
57 / 100
1054 ms7612 KiB
#pragma GCC optimization("Ofast") #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <bits/stdc++.h> using namespace std; using namespace __gnu_pbds; typedef long long ll; typedef long double ldb; typedef pair<int,int> pii; typedef pair<ll,ll> pll; typedef pair<ldb,ldb> pdd; #define ff(i,a,b) for(int i = a; i <= b; i++) #define fb(i,b,a) for(int i = b; i >= a; i--) #define trav(a,x) for(auto& a : x) #define sz(a) (int)(a).size() #define fi first #define se second #define pb push_back #define lb lower_bound #define ub upper_bound #define all(a) a.begin(), a.end() #define rall(a) a.rbegin(), a.rend() mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); template<typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; // os.order_of_key(k) the number of elements in the os less than k // *os.find_by_order(k) print the k-th smallest number in os(0-based) const int mod = 1000000007; const int inf = 1e9 + 5; const int mxN = 1000005; int n, q; string s, t; int d[mxN]; bool calc(){ ff(i,1,n - 1){ int x = s[i] - 'a'; int y = t[i] - 'a'; y = (y + d[i]) % 26; int r = (x - y + 26) % 26; d[i + 1] = r; } return (d[n] == (s[n] - t[n] + 26) % 26); } int main(){ cin.tie(0)->sync_with_stdio(0); cin >> n >> q >> s >> t; s = ' ' + s; t = ' ' + t; cout << (calc() == 1 ? "da" : "ne") << '\n'; while(q--){ int pos; char c; cin >> pos >> c; s[pos] = c; cout << (calc() == 1 ? "da" : "ne") << '\n'; } return 0; } /* 3 1 bbc ced 1 a 6 0 berlio pjesni // probati bojenje sahovski */

Compilation message (stderr)

Main.cpp:1: warning: ignoring '#pragma GCC optimization' [-Wunknown-pragmas]
    1 | #pragma GCC optimization("Ofast")
      |
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