Submission #971458

#	Time	Username	Problem	Language	Result	Execution time	Memory
971458		KiaRez	Rainy Markets (CCO22_day1problem2)	C++17	25 / 25	474 ms	106980 KiB

Main

/*
    IN THE NAME OF GOD
*/
#include <bits/stdc++.h>

// #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
// #pragma GCC optimize("O3")
// #pragma GCC optimize("unroll-loops")

using namespace std;

typedef long long ll;
typedef pair<ll, ll> pll;
typedef pair<int, int> pii;
typedef long double ld;

#define F                                      first
#define S                                      second
#define Mp                                     make_pair
#define pb                                     push_back
#define pf                                     push_front
#define size(x)                                ((ll)x.size())
#define all(x)                                 (x).begin(),(x).end()
#define kill(x)		                           cout << x << '\n', exit(0);
#define fuck(x)                                cout << "(" << #x << " , " << x << ")" << endl
#define endl                                   '\n'

const int N = 1e6+23, lg = 18;
ll Mod = 1e9+7; //998244353;

inline ll MOD(ll a, ll mod=Mod) {a%=mod; (a<0)&&(a+=mod); return a;}
inline ll poww(ll a, ll b, ll mod=Mod) {
    ll ans = 1;
    a=MOD(a, mod);
    while (b) {
        if (b & 1) ans = MOD(ans*a, mod);
        b >>= 1;
        a = MOD(a*a, mod);
    }
    return ans;
}

ll n, ans, res[3][N], b[N], p[N], u[N], dp[N], par[N];
// 0->l 1->mid 2->r
int main () {
	ios_base::sync_with_stdio(false), cin.tie(0);

	cin>>n;
    for(int i=1; i<=n; i++) cin>>b[i];
    for(int i=1; i<=n-1; i++) cin>>p[i];
    for(int i=1; i<=n-1; i++) cin>>u[i];

    for(int i=1; i<n; i++) {
        ll tmp = min(b[i]-res[2][i-1], p[i]);
        p[i] -= tmp; res[0][i] = tmp;
        tmp = min(u[i], p[i]);
        p[i] -= tmp; res[1][i] = tmp;
        tmp = min(b[i+1], p[i]);
        p[i] -= tmp; res[2][i] = tmp;
    }

    for(int i=n-1; i>=1; i--) {
        ll tmp = min(res[1][i], b[i+1]-res[2][i]-res[0][i+1]);
        res[1][i] -= tmp; res[2][i] += tmp;
        tmp = min(res[0][i], b[i+1]-res[2][i]-res[0][i+1]);
        res[0][i] -= tmp; res[2][i] += tmp;
    }

    for(int i=1; i<=n; i++) {
        if(p[i] > 0) {
            cout<<"NO\n";
            return 0;
        }
        ans += res[1][i];
    }

    cout<<"YES\n";
    cout<<ans<<endl;
    for(int i=1; i<n; i++) {
        cout<<res[0][i]<<' '<<res[1][i]<<' '<<res[2][i]<<endl;
    }

	return 0;
}

• Subtask 1: 5 / 5
• Subtask 2: 5 / 5
• Subtask 3: 6 / 6
• Subtask 4: 9 / 9