Submission #970770

#TimeUsernameProblemLanguageResultExecution timeMemory
9707700x34cCloud Computing (CEOI18_clo)C++17
0 / 100
2 ms1372 KiB
#include <bits/stdc++.h> #define ll long long #define pii pair<int, int> #define endl '\n' #define int ll using namespace std; struct node { int c, f, v; }; signed main() { ios_base::sync_with_stdio(0); cin.tie(0); int N, M; cin >> N; vector<node> pc(N); for (int i = 0; i < N; i++) { int c, f, v; cin >> c >> f >> v; pc[i] = {c, f, v}; } cin >> M; vector<node> qr(M); for (int i = 0; i < M; i++) { int c, f, v; cin >> c >> f >> v; qr[i] = {c, f, v}; } sort(pc.begin(), pc.end(), [&](node &a, node &b) { return a.f > b.f; }); sort(qr.begin(), qr.end(), [&](node &a, node &b) { return a.f > b.f; }); int dp[M][N]; memset(dp, 0, sizeof dp); int mx = 0; for (int i = 0; i < M; i++) for (int j = 0; j < N; j++) { // skip zakazku if (i + 1 < M) { dp[i + 1][j] = max(dp[i + 1][j], dp[i][j]); mx = max(mx, dp[i + 1][j]); } // skip pc if (j + 1 < N) { dp[i][j + 1] = max(dp[i][j + 1], dp[i][j]); mx = max(mx, dp[i][j + 1]); } // take next if (i + 1 < M && j + 1 < N && qr[i].f <= pc[j].f) { dp[i + 1][j + 1] = max(dp[i + 1][j + 1], dp[i][j] + (qr[i].v - pc[j].v)); mx = max(mx, dp[i + 1][j + 1]); } } cout << mx << endl; }
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