This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "shortcut.h"
#include <bits/stdc++.h>
#define INFLL (0x3f3f3f3f3f3f3f3fll)
using namespace std;
typedef long long ll;
inline void upmin(ll &a, ll b) { if(b < a) a = b; }
inline void upmax(ll &a, ll b) { if(a < b) a = b; }
const int MAXN = 1000005;
ll X[MAXN], L[MAXN];
int O[MAXN], OJ[MAXN];
int N; ll K, Ans;
bool isp(ll Y) {
ll xymx = -INFLL, xymn = INFLL, yxmx = -INFLL, yxmn = INFLL;
ll mn[2] = {INFLL, INFLL}, mx[2] = {-INFLL, -INFLL};
int mni[2] = {-1, -1}, mxi[2] = {-1, -1};
for(int oi = 0, i, oj = 0, j; oj < N; oj++) {
j = OJ[oj];
for(ll t = Y-X[j]-L[j], c; oi < N; oi++) {
i = O[oi]; c = X[i]-L[i];
if(-c <= t) break;
if(c < mn[0]) { swap(mn[0], c); swap(mni[0], i); }
if(c < mn[1]) { swap(mn[1], c); swap(mni[1], i); }
i = O[oi]; c = X[i]+L[i];
if(mx[0] < c) { swap(mx[0], c); swap(mxi[0], i); }
if(mx[1] < c) { swap(mx[1], c); swap(mxi[1], i); }
}
ll rmx = j == mxi[0] ? mx[1] : mx[0];
ll rmn = j == mni[0] ? mn[1] : mn[0];
ll a = Y-K + X[j]-L[j], b = K-Y + X[j]+L[j];
upmin(xymn, a+rmn); upmax(xymx, b+rmx);
upmin(yxmn, a-rmx); upmax(yxmx, b-rmn);
if(xymn < xymx || yxmn < yxmx) return false;
}
for(int s = 0, e = 0; s < N; s++) {
ll rmn = max(xymx-X[s], yxmx+X[s]);
ll rmx = min(xymn-X[s], yxmn+X[s]);
if(rmx < rmn) continue;
for(; e+1 < N && X[e] < rmn; e++);
for(; e && rmx < X[e]; e--);
if(rmn <= X[e]) return true;
}
return false;
}
ll getAns() {
ll mx = -INFLL;
for(int i = 0; i < N; i++) {
upmax(Ans, X[i]+L[i] + mx);
upmax(mx, L[i]-X[i]);
}
iota(O, O+N, 0); sort(O, O+N, [&](int a, int b) {
return L[a]-X[a] > L[b]-X[b];
});
iota(OJ, OJ+N, 0); sort(OJ, OJ+N, [&](int a, int b) {
return X[a]+L[a] < X[b]+L[b];
});
ll a = 0, b = 0;
for(int i = 0; i < N; i++) {
ll c = L[i];
if(a < c) swap(a, c);
if(b < c) swap(b, c);
}
ll s = a+b, e = Ans;
for(ll m; s < e;) {
m = (s+e) >> 1;
if(isp(m)) e = m;
else s = m+1;
}
return s;
}
long long find_shortcut(int n, std::vector<int> l, std::vector<int> d, int c) {
::N = n; ::K = c;
for(int i = 1; i < N; i++) ::X[i] = ::X[i-1] + l[i-1];
for(int i = 0; i < N; i++) ::L[i] = d[i];
return getAns();
}
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