Submission #969335

#	Time	Username	Problem	Language	Result	Execution time	Memory
969335		MinaRagy06	Boat (APIO16_boat)	C++17	0 / 100	2 ms	1368 KiB

boat

#include <bits/stdc++.h>
using namespace std;
#define ll long long

const int mod = 1e9 + 7;
struct mint {
	int v;
	mint(long long x) {
		if (x >= mod) x %= mod;
		v = x;
	}
	mint() {v = 0;}
	mint& operator+=(mint b) {
		if ((v += b.v) >= mod) {
			v -= mod;
		}
		return *this;
	}
	mint& operator-=(mint b) {
		if ((v -= b.v) < 0) {
			v += mod;
		}
		return *this;
	}
	mint& operator*=(mint b) {
		v = 1ll * v * b.v % mod;
		return *this;
	}
	mint power(mint a, int b) {
		mint ans = 1;
		while (b) {
			if (b & 1) {
				ans *= a;
			}
			a *= a, b >>= 1;
		}
		return ans;
	}
	mint& operator/=(mint b) {
		v = 1ll * v * power(b, mod - 2).v % mod;
		return *this;
	}
	friend mint operator+(mint a, mint b) {
		return a += b;
	}
	friend mint operator-(mint a, mint b) {
		return a -= b;
	}
	friend mint operator*(mint a, mint b) {
		return a *= b;
	}
	friend mint operator/(mint a, mint b) {
		return a /= b;
	}
	friend istream& operator>>(istream &is, mint &a) {
		return is >> a.v;
	}
	friend ostream& operator<<(ostream &os, mint a) {
		return os << a.v;
	}
};
int main() {
	ios_base::sync_with_stdio(0), cin.tie(0);
	int n;
	cin >> n;
	array<int, 2> a[n];
	vector<int> v;
	for (int i = 0; i < n; i++) {
		cin >> a[i][0] >> a[i][1];
		v.push_back(a[i][0]);
		v.push_back(a[i][1]);
	}
	sort(v.begin(), v.end());
	v.resize(unique(v.begin(), v.end()) - v.begin());
	auto get = [&] (int x) {
		return lower_bound(v.begin(), v.end(), x) - v.begin();
	};
	int m = v.size();
	vector<int> gud[m];
	for (int i = 0; i < n; i++) {
		int l = get(a[i][0]), r = get(a[i][1]);
		for (int j = l; j <= r; j++) {
			gud[j].push_back(i + 1);
		}
	}
	mint dp[m + 1][n + 1];
	for (int j = 0; j <= n; j++) {
		dp[m][j] = 1;
	}
	v.push_back(v.back() + 1);
	for (int i = m - 1; i >= 0; i--) {
		for (int j = 0; j <= n; j++) {
			dp[i][j] = dp[i + 1][j];
			for (auto k : gud[i]) {
				if (j <= k) {
					dp[i][j] += dp[i + 1][k] * (v[i + 1] - v[i]);
					break;
				}
			}
		}
	}
	cout << dp[0][0] - 1 << '\n';
	return 0;
}

• Subtask 1: 0 / 9
• Subtask 2: 0 / 22
• Subtask 3: 0 / 27
• Subtask 4: 0 / 42