Submission #967489

#TimeUsernameProblemLanguageResultExecution timeMemory
967489Halym2007Split the sequence (APIO14_sequence)C++17
50 / 100
2029 ms70612 KiB
#include <bits/stdc++.h> using namespace std; #define ll long long #define pb push_back #define sz size() const int N = 1e5 + 5; ll a[N], dp[N][205], par[N][205], p[N]; int n, k; ll sum (int x, int y) { return p[y] - p[x - 1]; } int main () { // freopen ("sequence.in", "r", stdin); // freopen ("sequence.out", "w", stdout); // freopen ("input.txt", "r", stdin); cin >> n >> k; for (int i = 1; i <= n; ++i) { cin >> a[i]; } reverse (a + 1,a + n + 1); for (int i = 1; i <= n; ++i) { p[i] = p[i - 1] + a[i]; } // dp[i][j] i-cenli j grupba bolemde maximum value. for (int i = 2; i <= n; ++i) { for (int x = 2; x <= min (i, k + 1); ++x) { for (int j = x - 1; j < i; ++j) { ll val = dp[j][x - 1] + sum (j + 1, i) * sum (1, j); if (dp[i][x] <= val) { par[i][x] = j; dp[i][x] = val; } } } } // cout << dp[n][k + 1]; // return 0; vector <int> cyk; int y = k + 1, x = n; while (1) { x = par[x][y]; if (!x) break; cyk.pb (x); y--; } cout << dp[n][k + 1] << "\n"; assert ((int)cyk.sz == k); for (int i : cyk) { // cout << n - i - 1<< " "; cout << n - i << " "; // cout << i << "\n"; } return 0; }
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...