Submission #96686

#TimeUsernameProblemLanguageResultExecution timeMemory
96686jasony123123Match (CEOI16_match)C++11
100 / 100
17 ms11128 KiB
#define _CRT_SECURE_NO_WARNINGS #include <bits/stdc++.h> //#include <ext/pb_ds/tree_policy.hpp> //#include <ext/pb_ds/assoc_container.hpp> using namespace std; //using namespace __gnu_pbds; #define FOR(i,start,end) for(int i=start;i<(int)(end);i++) #define FORE(i,start,end) for(int i=start;i<=(int)end;i++) #define RFOR(i,start,end) for(int i = start; i>end; i--) #define RFORE(i,start,end) for(int i = start; i>=end; i--) #define all(a) a.begin(), a.end() #define mt make_tuple #define mp make_pair #define v vector #define sf scanf #define pf printf #define dvar(x) cout << #x << " := " << x << "\n" #define darr(x,n) FOR(i,0,n) cout << #x << "[" << i << "]" << " := " << x[i] << "\n" typedef long long ll; typedef long double ld; typedef pair<int, int > pii; typedef pair<ll, ll> pll; //template <class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; template<class T> void minn(T &a, T b) { a = min(a, b); } template<class T> void maxx(T &a, T b) { a = max(a, b); } void io() { #ifdef LOCAL_PROJECT freopen("input.in", "r", stdin); freopen("output.out", "w", stdout); #else #endif ios_base::sync_with_stdio(false); cin.tie(NULL); } const ll INF = 1e14; /***********************CEOI 2016 D2 Match*****************************************/ int N; string S, ans; int pre[100000][26]; void assign(int lo, int hi) { if (lo >= hi) return; if (S[hi] == S[lo]) { ans[lo] = '(', ans[hi] = ')'; assign(lo + 1, hi - 1); } else { int mid = pre[hi][S[lo] - 'a']; assert(lo < mid); ans[lo] = '(', ans[mid] = ')'; assign(lo + 1, mid - 1), assign(mid + 1, hi); } } bool possible() { stack<char> stac; FOR(i, 0, N) { if (stac.empty() || stac.top() != S[i]) stac.push(S[i]); else stac.pop(); } return stac.empty(); } int main() { io(); cin >> S; N = S.size(); ans.resize(N); if (!possible()) { cout << "-1\n"; return 0; } FOR(c, 0, 26) pre[0][c] = -1; FOR(i, 1, N) FOR(c, 0, 26) { if (S[i] == S[i - 1]) { if (0 <= i - 2 && S[i - 2] - 'a' == c) pre[i][c] = i - 2; else { if (i - 2 < 0) pre[i][c] = -1; else pre[i][c] = pre[i - 2][c]; } } else { int y = pre[i - 1][S[i] - 'a']; if (y - 1 < 0) pre[i][c] = -1; else if (S[y - 1] - 'a' == c) pre[i][c] = y - 1; else pre[i][c] = pre[y - 1][c]; } } //FOR(i, 0, N) { // FOR(c, 0, 2) { // cout << i << " " << char(c + 'a') << " = " << pre[i][c] << "\n"; // } //} assign(0, N - 1); cout << ans << "\n"; }
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