Submission #961086

#	Time	Username	Problem	Language	Result	Execution time	Memory
961086		Nurislam	Split the sequence (APIO14_sequence)	C++17	39 / 100	2061 ms	31836 KiB

sequence

///*                                                    __                    __                        __                    */
///*        ======     _      /| /|  __   _            /   |  |   /|  |   *  |    |  |  | /   /| |\  | /   |  |  * | /        */
///* \-       ||  |_| |_     / |/ | |  | |_  |-        |   |--|  /-|  |   |  \ \  |==|  |-   /=| | \ | |   |--|  | |-         */
///*          ||  | | |_    /     | |__|  _| |_        \__ |  | /  |  |__ |  __|  |  |  | \ /  | |  \| \__ |  |  | | \        */
///* 
// autor :: Rick Prime
#pragma GCC optimize("O3")
#include <bits/stdc++.h>
using namespace std;
#define pb push_back
#define ff first
#define ss second
#define all(x) x.begin(),x.end()
#define rall(x) x.rbegin(),x.rend()
#define int long long
typedef vector<int> vi;
typedef vector<double> vd;
typedef pair<int,int> pii;
typedef vector<pii> vii;
const int N = 2e5+50, inf = 1e18, mod = 1e9+7;

void solve(){
	int n, k;
	cin >> n >> k;
	int dp[n][k+1];
	memset(dp, 0, sizeof(dp));
	int a[n];
	for(int &i:a)cin >> i; 	
	int sf[n+1]{};
	for(int i = n-1; i >= 0; i--){
		sf[i] = a[i]+sf[i+1];
	}
	int pr[n][k];
	int ans = 0, ps = 0;
	for(int i = 0; i < n; i++){
		int sm = 0;
		for(int j = i-1; j >= 0; j--){
			sm = sf[j]-sf[i];
			for(int x = 0; x < k; x++){
				//dp[j][x] + sm*sf[i]
				//dp[i][x+1]
				if(dp[i][x+1] < dp[j][x] + sm*sf[i]){
					pr[i][x+1] = j;
					dp[i][x+1] = dp[j][x] + sm*sf[i];
				}
			}
		}
		if(dp[i][k] >= ans){
			ps = i;
			ans = dp[i][k];
		}
	}
	cout << ans << '\n';
	//for(int i = 0; i <= k; i++){
		//for(int j = 0; j < n; j++){
			//cout << dp[j][i] << ' ';
		//}cout << '\n';
	//}
	vi v;
	while(k){
		v.pb(ps);
		ps = pr[ps][k--];
	}reverse(all(v));
	for(auto i:v)cout << i << ' ';
	cout << '\n';
}

signed main(){
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    
    int tt = 1;
    //cin >> tt;
    while (tt--) {
        solve();
    }
}

• Subtask 1: 0 / 11
• Subtask 2: 11 / 11
• Subtask 3: 11 / 11
• Subtask 4: 17 / 17
• Subtask 5: 0 / 21
• Subtask 6: 0 / 29