Submission #960216

#TimeUsernameProblemLanguageResultExecution timeMemory
960216tvladm2009Sequence (APIO23_sequence)C++17
0 / 100
799 ms66016 KiB
#include <iostream> #include <complex> #include <vector> #include <string> #include <algorithm> #include <cstdio> #include <numeric> #include <cstring> #include <ctime> #include <cstdlib> #include <set> #include <map> #include <unordered_map> #include <unordered_set> #include <list> #include <cmath> #include <bitset> #include <cassert> #include <queue> #include <stack> #include <deque> #include <random> using namespace std; template<typename T1, typename T2> inline void chkmin(T1 &a, T2 b) {if (a > b) a = b;} template<typename T1, typename T2> inline void chkmax(T1 &a, T2 b) {if (a < b) a = b;} #define files(FILENAME) read(FILENAME); write(FILENAME) #define read(FILENAME) freopen((FILENAME + ".in").c_str(), "r", stdin) #define write(FILENAME) freopen((FILENAME + ".out").c_str(), "w", stdout) #define all(c) (c).begin(), (c).end() #define sz(c) (int)(c).size() #define left left228 #define right right228 #define y1 y1228 #define mp make_pair #define pb push_back #define y2 y2228 #define rank rank228 using ll = long long; using ld = long double; const string FILENAME = "input"; const int MAXN = 500228; vector<int> pos[MAXN]; pair<int, int> tree[4 * MAXN]; int lazy[4 * MAXN]; pair<int, int> join(pair<int, int> a, pair<int, int> b) { return mp(min(a.first, b.first), max(a.second, b.second)); } void push(int v, int tl, int tr) { if (tl < tr) { lazy[2 * v] += lazy[v]; lazy[2 * v + 1] += lazy[v]; } tree[v].first += lazy[v]; tree[v].second += lazy[v]; lazy[v] = 0; } void add(int v, int tl, int tr, int l, int r, int x) { push(v, tl, tr); if (l <= tl && tr <= r) { lazy[v] += x; push(v, tl, tr); return; } int tm = (tl + tr) / 2; if (l <= tm) { add(2 * v, tl, tm, l, min(tm, r), x); } if (tm + 1 <= l) { add(2 * v + 1, tm + 1, tr, max(l, tm + 1), r, x); } push(2 * v, tl, tm); push(2 * v + 1, tm + 1, tr); tree[v] = join(tree[2 * v], tree[2 * v + 1]); } pair<int, int> get(int v, int tl, int tr, int l, int r) { push(v, tl, tr); if (l <= tl && tr <= r) { return tree[v]; } int tm = (tl + tr) / 2; if (l <= tm && r <= tm) { return get(2 * v, tl, tm, l, r); } else if (tm + 1 <= l && tm + 1 <= r) { return get(2 * v + 1, tm + 1, tr, l, r); } else { return join(get(2 * v, tl, tm, l, tm), get(2 * v + 1, tm + 1, tr, tm + 1, r)); } } int sequence(int n, vector<int> a) { for (int i = 0; i < n; i++) { a[i]--; pos[a[i]].pb(i); } for (int i = 0; i < n; i++) { add(1, 0, n - 1, i, n - 1, 1); } int res = 1; vector<int> pref_min1(n), pref_min2(n), pref_max1(n), pref_max2(n), suff_min1(n), suff_min2(n), suff_max1(n), suff_max2(n); for (int val = 0; val < n; val++) { for (int i = 0; i < sz(pos[val]); i++) { pair<int, int> res = get(1, 0, n - 1, 0, pos[val][i]); pref_min1[i] = res.first; pref_max1[i] = res.second; res = get(1, 0, n - 1, pos[val][i], n - 1); suff_min1[i] = res.first; suff_max1[i] = res.second; } for (auto p: pos[val]) { add(1, 0, n - 1, p, n - 1, -2); } for (int i = 0; i < sz(pos[val]); i++) { pair<int, int> res = get(1, 0, n - 1, 0, pos[val][i]); pref_min2[i] = res.first; pref_max2[i] = res.second; res = get(1, 0, n - 1, pos[val][i], n - 1); suff_min2[i] = res.first; suff_max2[i] = res.second; } int l = 1, r = sz(pos[val]), sol = 0; while (l <= r) { int m = (l + r) / 2; bool ok = false; for (int i = 0; i + m - 1 < sz(pos[val]); i++) { if (pref_min1[i] <= suff_max1[i + m - 1] && suff_min1[i + m - 1] <= pref_max1[i]) { ok = true; } else if (pref_min2[i] <= suff_max2[i + m - 1] && suff_min2[i + m - 1] <= pref_max2[i]) { ok = true; } else if (pref_max1[i] <= suff_min1[i + m - 1] && suff_max2[i + m - 1] <= pref_min2[i]) { ok = true; } else if (suff_max1[i] <= pref_min1[i + m - 1] && pref_max2[i + m - 1] <= suff_min2[i]) { ok = true; } } if (ok == true) { l = m + 1; sol = m; } else { r = m - 1; } } chkmax(res, sol); } return res; } /** int main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); //read(FILENAME); int n; cin >> n; vector<int> a(n); for (int i = 0; i < n; i++) { cin >> a[i]; } cout << sequence(n, a) << '\n'; return 0; } **/
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