Submission #959443

#	TimeUTC-0	Username	Problem	Language	Result	Execution time	Memory
959443	2024-04-08 08:21:10	zeta7532	Alice, Bob, and Circuit (APIO23_abc)	C++17	8 / 100	131 ms	9928 KiB

abc

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#include "abc.h"
#include <bits/stdc++.h>
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
using namespace std;
using ll = long long;
const ll mod = 998244353;
#define fi first
#define se second
#define rep(i,n) for(ll i=0;i<n;i++)
#define all(x) x.begin(),x.end()
#define faster ios::sync_with_stdio(false);cin.tie(nullptr)
// you may find the definitions useful
const int OP_ZERO    = 0;  // f(OP_ZERO,    x0, x1) = 0
const int OP_NOR     = 1;  // f(OP_NOR,     x0, x1) = !(x0 || x1)
const int OP_GREATER = 2;  // f(OP_GREATER, x0, x1) = (x0 > x1)
const int OP_NOT_X1  = 3;  // f(OP_NOT_X1,  x0, x1) = !x1
const int OP_LESS    = 4;  // f(OP_LESS,    x0, x1) = (x0 < x1)
const int OP_NOT_X0  = 5;  // f(OP_NOT_X0,  x0, x1) = !x0
const int OP_XOR     = 6;  // f(OP_XOR,     x0, x1) = (x0 ^ x1)
const int OP_NAND    = 7;  // f(OP_NAND,    x0, x1) = !(x0 && x1)
const int OP_AND     = 8;  // f(OP_AND,     x0, x1) = (x0 && x1)
const int OP_EQUAL   = 9;  // f(OP_EQUAL,   x0, x1) = (x0 == x1)
const int OP_X0      = 10; // f(OP_X0,      x0, x1) = x0
const int OP_GEQ     = 11; // f(OP_GEQ,     x0, x1) = (x0 >= x1)
const int OP_X1      = 12; // f(OP_X1,      x0, x1) = x1
const int OP_LEQ     = 13; // f(OP_LEQ,     x0, x1) = (x0 <= x1)
const int OP_OR      = 14; // f(OP_OR,      x0, x1) = (x0 || x1)
 
 
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