Submission #958880

#	Time	Username	Problem	Language	Result	Execution time	Memory
958880		gaga999	Fish 2 (JOI22_fish2)	C++17	100 / 100	1405 ms	81336 KiB

fish2

// #pragma GCC optimize("Ofast,no-stack-protector")
// #pragma GCC optimize("O3,unroll-loops")
// #pragma GCC target("avx,avx2,bmi,bmi2,lzcnt,popcnt")
#include <bits/stdc++.h>
#define lowbit(x) ((x) & -(x))
#define ml(a, b) ((1ll * (a) * (b)) % M)
#define tml(a, b) (a) = ((1ll * (a) * (b)) % M)
#define ad(a, b) ((0ll + (a) + (b)) % M)
#define tad(a, b) (a) = ((0ll + (a) + (b)) % M)
#define mi(a, b) ((0ll + M + (a) - (b)) % M)
#define tmi(a, b) (a) = ((0ll + M + (a) - (b)) % M)
#define tmin(a, b) (a) = min((a), (b))
#define tmax(a, b) (a) = max((a), (b))
#define iter(a) (a).begin(), (a).end()
#define riter(a) (a).rbegin(), (a).rend()
#define init(a, b) memset((a), (b), sizeof(a))
#define cpy(a, b) memcpy((a), (b), sizeof(a))
#define uni(a) a.resize(unique(iter(a)) - a.begin())
#define size(x) (int)x.size()
#define pb emplace_back
#define mpr make_pair
#define ls(i) ((i) << 1)
#define rs(i) ((i) << 1 | 1)
#define INF 0x3f3f3f3f
#define NIF 0xc0c0c0c0
#define eps 1e-9
#define F first
#define S second
#define AC cin.tie(0)->sync_with_stdio(0)
using namespace std;
typedef long long llt;
typedef __int128_t lll;
typedef pair<int, int> pii;
typedef pair<double, double> pdd;
typedef pair<llt, llt> pll;
typedef complex<double> cd;
// const int M = 998244353;

// random_device rm;
// mt19937 rg(rm());
// default_random_engine rg(rm());
// uniform_int_distribution<int> rd(INT_MIN, INT_MAX);
// uniform_real_distribution<double> rd(0, M_PI);

void db() { cerr << "\n"; }
template <class T, class... U>
void db(T a, U... b) { cerr << a << " ", db(b...); }

inline char gc()
{
    const static int SZ = 1 << 16;
    static char buf[SZ], *p1, *p2;
    if (p1 == p2 && (p2 = buf + fread(p1 = buf, 1, SZ, stdin), p1 == p2))
        return -1;
    return *p1++;
}
void rd() {}
template <typename T, typename... U>
void rd(T &x, U &...y)
{
    x = 0;
    bool f = 0;
    char c = gc();
    while (!isdigit(c))
        f ^= !(c ^ 45), c = gc();
    while (isdigit(c))
        x = (x << 1) + (x << 3) + (c ^ 48), c = gc();
    f && (x = -x), rd(y...);
}

template <typename T>
void prt(T x)
{
    if (x < 0)
        putchar('-'), x = -x;
    if (x > 9)
        prt(x / 10);
    putchar((x % 10) ^ 48);
}
const llt MX = 1ll << 60;
const int N = 1e5 + 5;

struct P
{
    llt sum;
    int ans;
    vector<llt> lsm, rsm, lnd, rnd;
    vector<int> lnb, rnb;
    inline void ini(int v)
    {
        sum = v, ans = 1;
        lsm = rsm = vector<llt>(1, 0);
        lnd = rnd = vector<llt>(1, v);
        lnb = rnb = vector<int>(1, 0);
    }
} tr[N << 1];

P operator+(P &l, P &r)
{
    P p;
    int slr = size(l.rnd), srl = size(r.lnd);
    p.sum = l.sum + r.sum, p.ans = 0;
    p.lsm = l.lsm, p.rsm = r.rsm;
    p.lnd = l.lnd, p.rnd = r.rnd;
    p.lnb = l.lnb, p.rnb = r.rnb;
    for (int i = 0; i < srl; i++)
        if (r.lnd[i] > l.sum)
            p.lnd.pb(r.lnd[i] - l.sum), p.lsm.pb(r.lsm[i] + l.sum);
    p.lnb.resize(size(p.lnd), 0);
    if (size(p.lnd) > size(l.lnd))
        p.lnb[size(l.lnd)] = l.ans;
    else
        p.ans += l.ans;
    for (int i = 0; i < slr; i++)
        if (l.rnd[i] > r.sum)
            p.rnd.pb(l.rnd[i] - r.sum), p.rsm.pb(l.rsm[i] + r.sum);
    p.rnb.resize(size(p.rnd), 0);
    if (size(p.rnd) > size(r.rnd))
        p.rnb[size(r.rnd)] = r.ans;
    else
        p.ans += r.ans;
    l.rnb.pb(0), l.rnd.pb(MX), l.rsm.pb(l.sum);
    r.lnb.pb(0), r.lnd.pb(MX), r.lsm.pb(r.sum);
    auto move = [&](int p1, int p2, int num) -> void
    {
        // db(p1, p2, num);
        bool ok = 1;
        while (ok)
        {
            ok = 0;
            while (l.rnd[p1] <= r.lsm[p2])
                p1++, ok = 1;
            while (r.lnd[p2] <= l.rsm[p1])
                p2++, ok = 1;
        }
        if (p1 == slr && p2 == srl)
            p.ans += num;
        else if (p1 == slr)
        {
            int i = 0;
            while (p.lsm[i] < l.sum + r.lsm[p2])
                i++;
            assert(p.lsm[i] == l.sum + r.lsm[p2]);
            p.lnb[i] += num;
        }
        else if (p2 == srl)
        {
            int i = 0;
            while (p.rsm[i] < r.sum + l.rsm[p1])
                i++;
            assert(p.rsm[i] == r.sum + l.rsm[p1]);
            p.rnb[i] += num;
        }
    };
    for (int i = 0; i < slr; i++)
        if (l.rnb[i])
            move(i, 0, l.rnb[i]);
    for (int i = 0; i < srl; i++)
        if (r.lnb[i])
            move(0, i, r.lnb[i]);
    l.rnb.pop_back(), l.rnd.pop_back(), l.rsm.pop_back();
    r.lnb.pop_back(), r.lnd.pop_back(), r.lsm.pop_back();
    return p;
}

signed main()
{
    int n, q, x, a, b;
    rd(n);
    auto pul = [&](int i) -> void
    {
        tr[i] = tr[ls(i)] + tr[rs(i)];
    };
    auto cg = [&](int p, int v) -> void
    {
        p += n - 1, tr[p].ini(v);
        for (p >>= 1; p; p >>= 1)
            pul(p);
    };
    auto qy = [&](int l, int r) -> int
    {
        l += n - 1, r += n - 1;
        if (l == r)
            return tr[l].ans;
        // P pp = tr[l++];
        // for (; l <= r; l++)
        //     pp = pp + tr[l];
        // return pp.ans;
        P p1 = tr[l++], p2 = tr[r--];
        for (; l <= r; l >>= 1, r >>= 1)
        {
            if (l & 1)
                p1 = p1 + tr[l++];
            if (~r & 1)
                p2 = tr[r--] + p2;
        }
        return (p1 + p2).ans;
    };
    // for (int i = 1; i < n; i++)
    // {
    //     tr[i] = tr[i - 1] + tr[i], db(tr[i].ans, tr[i].sum);
    //     for (int p : tr[i].rnb)
    //         cerr << p << ' ';
    //     cerr << '\n';
    //     for (int p : tr[i].rsm)
    //         cerr << p << ' ';
    //     cerr << '\n';
    // }
    for (int i = 0; i < n; i++)
        rd(x), tr[i + n].ini(x);
    for (int i = n - 1; i > 0; i--)
        pul(i);
    rd(q);
    while (q--)
    {
        rd(x, a, b);
        if (x == 1)
            cg(a, b);
        else
            prt(qy(a, b)), putchar('\n');
    }
}

• Subtask 1: 5 / 5
• Subtask 2: 8 / 8
• Subtask 3: 12 / 12
• Subtask 4: 23 / 23
• Subtask 5: 35 / 35
• Subtask 6: 17 / 17