Submission #957815

#	Time	Username	Problem	Language	Result	Execution time	Memory
957815		BhavayGoyal	Snake Escaping (JOI18_snake_escaping)	C++14	12 / 100	1002 ms	65536 KiB

snake_escaping

#include <bits/stdc++.h>
using namespace std;

#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;

template<class T> using oset = 
            tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;

#define ll long long
#define ld long double
#define ar array
#define vi vector<int>
#define vii vector<vector<int>>
#define pii pair<int, int>
#define pb push_back
#define all(x) x.begin(), x.end()
#define f first
#define s second
#define endl "\n"

const int MOD = 1e9+7;
const int inf = 1e9;
const ll linf = 1e18;

const int d4i[4]={-1, 0, 1, 0}, d4j[4]={0, 1, 0, -1};
const int d8i[8]={-1, -1, 0, 1, 1, 1, 0, -1}, d8j[8]={0, 1, 1, 1, 0, -1, -1, -1};

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());


// -------------------------------------------------- Main Code --------------------------------------------------

const int N = (1<<20)+5;
int n, q, arr[N];
unordered_map<string, int> mp;

int sol(string &s) {
    if (mp.find(s) != mp.end()) {
        return mp[s];
    }
    int ans = 0;
    for (int i = 0; i < n; i++) {
        if (s[i] == '?') {
            s[i] = '0';
            ans = (ans + sol(s));
            s[i] = '1';
            ans = (ans + sol(s));
            s[i] = '?';
            break;
        }
    }
    return mp[s] = ans;
}

void sol() {
    cin >> n >> q;
    for (int i = 0; i < (1<<n); i++) {char x; cin >> x; arr[i] = x-'0';}

    for (int i = 0; i < (1<<n); i++) {
        string s(n,'0');
        for (int j = 0; j < n; j++) {
            if (i&(1<<j)) s[j] = '1';
        }
        reverse(all(s));
        mp[s] = arr[i];
    }

    string s(n, '?');
    sol(s);

    while (q--) {
        string s; cin >> s;
        cout << sol(s) << endl;
    }
}

int main () {
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);

    int t = 1;
    // cin >> t; 
    while (t--) {
        sol();
    }
    return 0;
}

• Subtask 1: 5 / 5
• Subtask 2: 7 / 7
• Subtask 3: 0 / 10
• Subtask 4: 0 / 53
• Subtask 5: 0 / 25