Submission #956389

#	Time	Username	Problem	Language	Result	Execution time	Memory
956389		Nelt	Jakarta Skyscrapers (APIO15_skyscraper)	C++17	57 / 100	1029 ms	86948 KiB

skyscraper

#include <bits/stdc++.h>
#define ll long long
#define endl "\n"
using namespace std;
 
void solve()
{
    ll n, m;
    cin >> n >> m;
    ll b[m], p[m];
    vector<ll> eq[n];
    for (ll i = 0; i < m; i++)
        cin >> b[i] >> p[i], eq[b[i]].push_back(p[i]);
    for (ll i = 0; i < n; i++)
        sort(eq[i].begin(), eq[i].end(), greater());
    map<ll, ll> dist[n];
    dist[b[0]][p[0]] = 0;
    priority_queue<pair<ll, pair<ll, ll>>> q;
    q.push(make_pair(0, make_pair(p[0], b[0])));
    while (!q.empty())
    {
        auto [dst, x] = q.top(); 
        auto [j, i] = x;
        dst = -dst;
        q.pop();
        if (dst > dist[i][j])   continue;
        if (i == b[1])
        {
            cout << dst << endl;
            return;
        }
        if (i - j >= 0 and !dist[i - j].count(j) and dist[i - j].size() <= 3000)
            dist[i - j][j] = dst + 1, q.push(make_pair(-(dst + 1), make_pair(j, i - j)));
        if (i + j < n and !dist[i + j].count(j) and dist[i + j].size() <= 3000)
            dist[i + j][j] = dst + 1, q.push(make_pair(-(dst + 1), make_pair(j, i + j)));
        for (ll k : eq[i])
        {
            if (i - k >= 0 and !dist[i - k].count(k) and dist[i - k].size() <= 3000)
                dist[i - k][k] = dst + 1, q.push(make_pair(-(dst + 1), make_pair(k, i - k)));
            if (i + k < n and !dist[i + k].count(k) and dist[i + k].size() <= 3000)
                dist[i + k][k] = dst + 1, q.push(make_pair(-(dst + 1), make_pair(k, i + k)));
        }
        eq[i].clear();
        if (!dist[b[1]].empty())
        {
            ll ans = 1e18;
            for (auto j : dist[b[1]])
                ans = min(ans, j.second);
            cout << ans << endl;
            return;
        }
    }
    cout << "-1\n";
}
 
signed main()
{
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    ll t = 1;
    // precomp();
    // cin >> t;
    for (ll i = 1; i <= t; i++)
        solve();
    cerr << "\nTime elapsed: " << clock() * 1000.0 / CLOCKS_PER_SEC << " ms\n";
}

• Subtask 1: 10 / 10
• Subtask 2: 12 / 12
• Subtask 3: 14 / 14
• Subtask 4: 21 / 21
• Subtask 5: 0 / 43