Submission #955428

#TimeUsernameProblemLanguageResultExecution timeMemory
955428yoav_sDiversity (CEOI21_diversity)C++17
4 / 100
13 ms3420 KiB
#include <bits/stdc++.h> using namespace std; typedef long long ll; typedef vector<ll> v; typedef vector<v> vv; typedef vector<vv> vvv; typedef pair<ll,ll> p; typedef vector<p> vp; typedef vector<vp> vvp; typedef vector<vvp> vvvp; typedef pair<ll, p> tri; typedef vector<tri> vtri; typedef vector<vtri> vvtri; typedef vector<vvtri> vvvtri; typedef vector<bool> vb; typedef vector<vb> vvb; typedef vector<vvb> vvvb; #define f first #define s second #define pb push_back #define eb emplace_back #define all(v) (v).begin(),(v).end() const ll INF = 1e18; const ll mod = 1e9 + 7; const ll maxValue = 3e5; ll evaluate(v &segments) { ll N = 0; for (ll x : segments) N += x; ll l = 0; ll res = 0; for (ll x : segments) { ll r = l + x - 1; res += ((r - l + 1) * (r - l + 2)) / 2 + l * (N - r - 1) + (r - l + 1) * l + (r - l + 1) * (N - r - 1); l += x; } return res; } ll limitingFactor(v &segments) { ll N = 0; for (ll x : segments) N += x; ll l = 0; ll res = 0; for (ll x : segments) { ll r = l + x - 1; res += (N - r - 1) * l; l += x; } return res; } int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); ll N, Q; cin >> N >> Q; v a(N); for (ll i = 0; i < N; i++) cin >> a[i]; sort(all(a)); v histogram(maxValue + 1, 0); for (ll x : a) histogram[x]++; v segments; for (ll i = 0; i <= maxValue; i++) if (histogram[i] > 0) segments.pb(histogram[i]); sort(all(segments)); v bestPerm(segments.size()); copy(all(segments),bestPerm.begin()); if (segments.size() == 1) { cout << evaluate(bestPerm) << "\n"; return 0; } ll cur = limitingFactor(segments); ll mini = cur; double time = 0.9999; ll iterations = 100000; while (iterations--) { ll i = rand() % (segments.size()); ll j = rand() % segments.size(); swap(segments[i], segments[j]); ll newCur = limitingFactor(segments); if (newCur < mini) {copy(all(segments),bestPerm.begin()); mini = newCur;} if (newCur > cur && (rand() % ((ll)exp((cur - newCur) * 2 / time) + 1)) != 0) swap(segments[i], segments[j]); else cur = newCur; time *= 0.9999; } cout << evaluate(bestPerm) << "\n"; return 0; }
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