Submission #954634

#	Time	Username	Problem	Language	Result	Execution time	Memory
954634		hengliao	Olympiads (BOI19_olympiads)	C++17	44 / 100	1683 ms	262144 KiB

olympiads

#pragma GCC optimize("Ofast")
 
#include<bits/stdc++.h>
using namespace std;
 
#define F first
#define S second
#define pb push_back
#define vll vector<ll>
#define pll pair<ll, ll>
typedef long long ll;
 
const ll A=9828401843;
const ll B=1e9+78328738;
 
const ll inf=1e17;
 
struct team{
    vll v;
    ll n, id;
 
    void init(ll tn){
        n=tn;
        v=vll(n, -inf);
    }
    void rd(ll tn){
        n=tn;
        v.resize(n);
        for(ll i=0;i<n;i++){
            cin>>v[i];
        }
    }
    void mxwith(vll &cur){
        for(ll i=0;i<n;i++){
            cur[i]=max(cur[i], v[i]);
        }
    }
 
    void operator=(const team &tar){
        for(ll i=0;i<n;i++){
            v[i]=tar.v[i];
        }
        id=tar.id;
    }
 
    bool operator<(const team &tar) const{
        return id<tar.id;
    }
};
 
const ll mxN=505;
 
ll n, k, c;
vector<team> a;
vector<team> on;
vector<team> best;
bool use[mxN];
unordered_map<ll, ll> done;
 
ll hs(const vll &tar){
    ll re=0;
    vll tep=tar;
    sort(tep.begin(), tep.end());
    for(ll i=0;i<k;i++){
        re=(re*A+tep[i])%B;
    }
    return re;
}
 
ll gt(vector<team> &tar, vll &cur){
    for(ll i=0;i<k;i++){
        tar[i].mxwith(cur);
    }
    ll re=0;
    for(ll i=0;i<k;i++){
        re+=cur[i];
    }
    return re;
}
 
ll gt2(vll &tar){
    ll re=0;
    for(ll i=0;i<k;i++){
        ll cur=0;
        for(ll j=0;j<k;j++){
            cur=max(cur, a[tar[j]].v[i]);
        }
        re+=cur;
    }
    return re;
}
 
void solve(){
    memset(use, 0, sizeof(use));
    cin>>n>>k>>c;
    a.resize(n);
    for(ll i=0;i<k;i++){
        team tep;
        tep.init(k);
        best.pb(tep);
    }
    for(ll i=0;i<n;i++){
        a[i].rd(k);
        a[i].id=i;
    }
    for(ll i=0;i<n;i++){
        for(ll j=0;j<k;j++){
            if(a[i].v[j]>best[j].v[j]){
                best[j]=a[i];
            }
        }
    }
    ll cnt=0;
    vector<team> be;
    for(ll i=0;i<k;i++){
        if(use[best[i].id]){
            cnt++;
        }
        else{
            use[best[i].id]=1;
            be.pb(best[i]);
        }
    }
    while(cnt--){
        for(ll i=0;i<n;i++){
            if(!use[i]){
                be.pb(a[i]);
                use[i]=1;
                break;
            }
        }
    }
    priority_queue<pair<ll, vll>> pq;
    vll cur(k, -inf);
    ll re=gt(be, cur);
    vll tep;
    for(ll i=0;i<n;i++){
        if(use[i]){
            tep.pb(i);
            //cout<<i<<' ';
        }
    }
    //cout<<'\n';
    //cout<<re<<'\n';
    pq.push({re, tep});
    done[hs(tep)]++;
    ll ans;
    //assert(1);
    //bool b=0;
    vll cur2;
    for(ll i=0;i<c && !pq.empty();i++){
        pair<ll, vll> now=pq.top(); pq.pop();
        ans=now.F;
        vll tep=now.S;
        memset(use, 0, sizeof(use));
        for(ll j=0;j<k;j++){
            use[tep[j]]=1;
        }
        for(ll pos=0;pos<k;pos++){
            vll nxt;
            for(ll j=0;j<k;j++){
                if(j==pos) continue;
                //assert(tep[j]<n);
                /*if(tep[j]>=n){
                    cout<<"bad "<<i<<'\n';
                    for(auto it:tep){
                        cout<<it<<' ';
                    }
                    cout<<'\n';
                    b=1;
                    break;
                }*/
                nxt.pb(tep[j]);
            }
            //if(b) break;
            cur=vll(k, -inf);
            for(auto it:nxt){
                for(ll j=0;j<k;j++){
                    cur[j]=max(cur[j], a[it].v[j]);
                }
            }
            for(ll j=0;j<n;j++){
                if(!use[j]){
                    nxt.pb(j);
                    ll h=hs(nxt);
                    if(done[h]){
                        nxt.pop_back();
                    }
                    else{
                        done[h]++;
                        cur2=cur;
                        for(ll ii=0;ii<k;ii++){
                            cur2[ii]=max(cur2[ii], a[j].v[ii]);
                        }
                        ll re=0;
                        for(ll ii=0;ii<k;ii++){
                            re+=cur2[ii];
                        }
                        pq.push({re, nxt});
                        nxt.pop_back();
                    }
                    //done.insert(hs(nxt));
                }
            }
        }
    }
    cout<<ans<<'\n';
}
 
int main(){
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
 
    solve();
    return 0;
}

• Subtask 1: 13 / 13
• Subtask 2: 31 / 31
• Subtask 3: 0 / 24
• Subtask 4: 0 / 32