This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define endl '\n'
#define pii pair<int, int>
const int MX = 1e5 + 5;
vector<pair<int, pii>> gr[MX];
int L[MX], R[MX], f[MX];
int ans[MX];
struct node{
int good, sum;
node *l, *r;
node(){
this->good = this->sum = 0;
this->l = this->r = NULL;
}
};
struct SMT{
// vector<node> tree;
node *root;
int n;
SMT(){
// tree.assign(4*n + 5, node());
this->n = 1e9 + 5;
this->root = new node();
};
node *update(node *cur, int l, int r, int u, int v, int val){
if(r < u || l > v){
return cur;
}
if(cur == NULL){
cur = new node();
}
if(u <= l && r <= v){
cur->good += val;
cur->sum = (cur->good ? r-l+1 : (cur->l ? cur->l->sum : 0) + (cur->r ? cur->r->sum : 0));
// tree[id].good += val;
// tree[id].sum = (tree[id].good ? r-l+1 : tree[2*id].sum + tree[2*id+1].sum);
return cur;
}
int mid = (l + r) >> 1;
cur->l = update(cur->l, l, mid, u, v, val);
cur->r = update(cur->r, mid+1, r, u, v, val);
// tree[id].sum = (tree[id].good ? r-l+1 : tree[ID].sum + tree[ID|1].sum);
cur->sum = (cur->good ? r-l+1 : (cur->l ? cur->l->sum : 0) + (cur->r ? cur->r->sum : 0));
return cur;
}
void update(int l, int r, int val){
root = update(root, 1, n, l, r, val);
}
int get(node *cur, int l, int r, int u, int v){
if(r < u || l > v || cur == NULL){
return 0;
}
if(u <= l && r <= v){
return cur->sum;
}
int mid = (l + r) >> 1;
return get(cur->l, l, mid, u, v) + get(cur->r, mid+1, r, u, v);
}
};
SMT smt;
void dfs(int u, int p){
ans[u] = smt.root->sum;
for(pair<int, pii> e : gr[u]){
int v, l, r;
v = e.first;
tie(l, r) = e.second;
if(v != p){
smt.update(l, r, 1);
dfs(v, u);
smt.update(l, r, -1);
}
}
}
int32_t main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
// freopen("main.inp","r",stdin);
// freopen("main.out","w",stdout);
int n, m;
cin>>n>>m;
for(int i=1; i<n; ++i){
int u, v, l, r;
cin>>u>>v>>l>>r;
gr[u].push_back({v, {l, r}});
gr[v].push_back({u, {l, r}});
}
dfs(1, 0);
for(int i=2; i<=n; ++i){
cout<<ans[i]<<endl;
}
return 0;
}
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