Submission #953480

#	Time	Username	Problem	Language	Result	Execution time	Memory
953480		tnknguyen_	Vinjete (COI22_vinjete)	C++14	27 / 100	104 ms	66840 KiB

Main

#include <bits/stdc++.h>
using namespace std;
#define int long long
#define endl '\n' 
#define pii pair<int, int>

const int MX = 1e5 + 5;
vector<pair<int, pii>> gr[MX];
int L[MX], R[MX], f[MX];
int ans[MX];

struct node{
    int good, sum;
    node(){
        good = sum = 0;
    }
};

struct SMT{ 
    vector<node> tree;
    int n = 1e5 + 5;

    SMT(){
        tree.assign(4*n + 5, node());
    };

    void update(int id, int l, int r, int u, int v, int val){
        if(r < u || l > v){
            return;
        }
        if(u <=l && r <= v){
            tree[id].good += val;
            tree[id].sum = (tree[id].good ? r-l+1 : tree[2*id].sum + tree[2*id+1].sum);
            return;
        }
        int mid = (l + r) >> 1, ID = (id << 1);
        update(ID, l, mid, u, v, val);
        update(ID|1, mid+1, r, u, v, val);

        tree[id].sum = (tree[id].good ? r-l+1 : tree[ID].sum + tree[ID|1].sum);
    }

    void update(int l, int r, int val){
        update(1, 1, n, l, r, val);
    }

    int get(int id, int l, int r, int u, int v){
        if(r < u || l > v){
            return 0;
        }
        if(u <= l && r <= v){
            return tree[id].sum;
        }
        int mid = (l + r) >> 1, ID = (id << 1);
        return get(ID, l, mid, u, v) + get(ID|1, mid+1, r, u, v);
    }
};

SMT smt;

void dfs(int u, int p){
    ans[u] = smt.tree[1].sum;
    for(pair<int, pii> e : gr[u]){
        int v, l, r;
        v = e.first;
        tie(l, r) = e.second;
        if(v != p){
            smt.update(l, r, 1);
            dfs(v, u);
            smt.update(l, r, -1);
        }
    }
}

int32_t main() {
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);

    //freopen("main.inp","r",stdin);
    //freopen("main.out","w",stdout);

    int n, m;
    cin>>n>>m;

    for(int i=1; i<n; ++i){
        int u, v, l, r;
        cin>>u>>v>>l>>r;
        gr[u].push_back({v, {l, r}});
        gr[v].push_back({u, {l, r}});
    }

    dfs(1, 0);

    for(int i=2; i<=n; ++i){
        cout<<ans[i]<<endl;
    }

    return 0;
}

• Subtask 1: 11 / 11
• Subtask 2: 0 / 13
• Subtask 3: 16 / 16
• Subtask 4: 0 / 29
• Subtask 5: 0 / 31