Submission #953334

#	Time	Username	Problem	Language	Result	Execution time	Memory
953334		Itamar	Land of the Rainbow Gold (APIO17_rainbow)	C++14	0 / 100	422 ms	69400 KiB

rainbow

#include "rainbow.h"
#include <iostream>
using namespace std;
#include <vector>
#define vi vector<int>
#define ll long long
#include <algorithm>
#include <set>
#include <string>
#include <bitset>
#include <cmath>
#include <math.h>
#define pll pair<ll,ll>
#define vll vector<ll>
#define pi pair<int,int>
#include <map>
#include <queue>
#define x first
#define y second
#define pd pair<double,double>

map<pi, bool> m;
void init(int R, int C, int sr, int sc, int M, char* S) {
    m[{sr,sc}] = 1;
    for (int i = 0; i < M; i++) {
        if (S[i] == 'E')sr++;
        if (S[i] == 'W')sr--;
        if (S[i] == 'N')sc--;
        if (S[i] == 'S')sc++;
        m[{sr, sc}] = 1;
    }
}

int colour(int ar, int ac, int br, int bc) {
    map<pi, bool> mt = m;
    swap(ar, ac); swap(br, bc);
    ar--, ac--, br++, bc++;
    for (int i = ar; i <= br; i++) {
        m[{i, ac}] = 1;
        m[{i, bc}] = 1;
    }
    for (int i = ac; i <= bc; i++) {
        m[{ar, i}] = 1;
        m[{br, i}] = 1;
    }
    int v=0, e=0, t=0,r=0;
    for (pair<pi, bool> p : m) {
        int a = p.x.x, b = p.x.y;
        if (a < ar || a > br || b < ac || b > bc)m[p.x]=0;
    }
    for (pair<pi,bool> p : m) {
        if (p.second == 0)continue;
        int a = p.x.x, b = p.x.y;
        if (a < ar || a > br || b < ac || b > bc)continue;

        v++;
        bool g = m[{a + 1, b}], h = m[{a, b + 1}], i = m[{a - 1, b}], j = m[{a, b - 1}];
        bool k = m[{a + 1, b - 1}], l = m[{a + 1, b + 1}];
        e += k;
        e += g;
        e += l;
        e += j;

        t += (g + i) * (h + j);
        r += g * h * l;
    }
    int pl = 1;
    map<pi, bool> vis;
    if (v == 2*(br - ar + bc - ac) )pl = 0;
    for (pair<pi, bool> p : m) {
        if (p.y) {
            int a = p.x.x, b = p.x.y;
            if (a == ar || a == br || b == bc || b == ac)continue;
            if (a == ar + 1 || a == br - 1 || b == ac + 1 || b == bc - 1)pl = 0;
        }
    }
    m = mt;
    return 1+e-v-t+r+pl;
}

• Subtask 1: 0 / 11
• Subtask 2: 0 / 12
• Subtask 3: 0 / 24
• Subtask 4: 0 / 27
• Subtask 5: 0 / 26