Submission #9513

#	Time	Username	Problem	Language	Result	Execution time	Memory
9513		myungwoo	Phibonacci (kriii2_P)	C++14	1 / 4	0 ms	1088 KiB

P

#include <stdio.h>

typedef long long lld;

const int MOD = 1e9 + 7;

lld N, K;

struct MAT{
	int m[2][2];
	MAT operator * (const MAT &ot)const{
		MAT ret={0, };
		int i, j, k;
		for (i=0;i<2;i++) for (j=0;j<2;j++) for (k=0;k<2;k++)
			ret.m[i][j] = (ret.m[i][j]+(lld)m[i][k]*ot.m[k][j]%MOD)%MOD;
		return ret;
	}
} P[40];

struct TERM{
	TERM(lld p, lld q){
		a = p%MOD, b = q%MOD;
	}
	int a, b;
	TERM operator * (const TERM &ot)const{
		return TERM((((lld)a*ot.a%MOD+(lld)a*ot.b%MOD)%MOD+(lld)b*ot.a%MOD)%MOD, ((lld)a*ot.a%MOD+(lld)b*ot.b%MOD)%MOD);
	}
};

int fibo(lld n)
{
	MAT t ={1, 0, 0, 1};
	if (n < 0) return 1;
	for (int i=0;i<40;i++,n>>=1) if (n&1) t = t*P[i];
	return t.m[0][1];
}

TERM pow(TERM a, lld b)
{
	TERM v = a, ret(0, 1);
	for (;b;b>>=1, v=v*v) if (b&1) ret = ret*v;
	return ret;
}

int pow(int a, lld b)
{
	int v = a, ret = 1;
	for (;b;b>>=1,v=(lld)v*v%MOD) if (b&1) ret = (lld)ret*v%MOD;
	return ret;
}

int main()
{
	int i;
	MAT t ={1, 1, 1, 0};
	P[0] = t;
	for (i=1;i<40;i++) P[i] = P[i-1]*P[i-1];
	scanf("%lld%lld", &N, &K);
	TERM p(fibo(N), fibo(N-1));
	TERM q = pow(p, K);
	int x = (lld)q.a*pow(fibo(K), MOD-2)%MOD;
	int y = (q.b-(lld)x*fibo(K-1)%MOD+MOD)%MOD;
	printf("%d %d\n", x, y);
}

• Subtask 1: 1 / 1
• Subtask 2: 0 / 3