# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
950129 | quanlt206 | Gap (APIO16_gap) | C++17 | 0 ms | 0 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
//#include "gap.h"
#include<bits/stdc++.h>
#define X first
#define Y second
#define all(x) begin(x), end(x)
#define FOR(i, a, b) for(int i = (a); i <= (b); i++)
#define FORD(i, b, a) for(int i = (b); i >= (a); i--)
#define REP(i, a, b) for (int i = (a); i < (b); i++)
#define mxx max_element
#define mnn min_element
#define SQR(x) (1LL * (x) * (x))
#define MASK(i) (1LL << (i))
#define Point Vector
#define left Left
#define right Right
#define div Div
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef double db;
typedef long double ld;
typedef pair<db, db> pdb;
typedef pair<ld, ld> pld;
typedef pair<int, int> pii;
typedef pair<int, pii> piii;
typedef pair<ll, ll> pll;
typedef pair<ll, pll> plll;
typedef pair<ll, int> pli;
typedef pair<ll, pii> plii;
template<class A, class B>
bool maximize(A& x, B y) {
if (x < y) return x = y, true; else return false;
}
template<class A, class B>
bool minimize(A& x, B y) {
if (x > y) return x = y, true; else return false;
}
/* END OF TEMPLATE */
const int N = 1e5 + 7;
ll a[N], b[N];
int n;
int cntQuery = 0;
ll sub1(int n) {
int l = 1, r = n;
ll s = 0, t = 1e18;
while (l <= r) {
ll* mn = new ll();
ll* mx = new ll();
MinMax(s, t, mn, mx);
a[l] = *mn;
a[r] = *mx;
l++;
r--;
s = *mn + 1;
t = *mx - 1;
}
ll res = 0;
REP(i, 1, n) maximize(res, a[i + 1] - a[i]);
return res;
}
ll findGap(int T, int n) {
// if (T == 1 || n <= 7) return sub1(n);
a[0] = -1;
ll res = 0;
int i = 1;
ll* mn = new ll();
ll* mx = new ll();
MinMax(0, 1e18, mn, mx);
ll Max = *mx, Min = *mn;
res = (Max - Min) / (n - 1);
if (1LL * res * (n - 1) < Max - Min) res++;
vector<pll> A;
for (ll i = Min; i <= Max; i+=res) {
ll* mn = new ll();
ll* mx = new ll();
MinMax(i, i + res - 1, mn, mx);
// if (!A.empty() && *mn != -1) maximize(res, *mn - A.back().Y);
if (*mn != -1) A.push_back({*mn, *mx});
}
REP(i, 1, (int)A.size()) maximize(res, A[i].X - A[i - 1].Y);
return res;
}