Submission #950061

#	Time	Username	Problem	Language	Result	Execution time	Memory
950061		Alihan_8	Planine (COCI21_planine)	C++17	0 / 110	2 ms	604 KiB

Main

#include <bits/stdc++.h>

using namespace std;

#define all(x) x.begin(), x.end()
#define ar array
#define pb push_back
#define ln '\n'
#define int long long

using i64 = long long;

template <class F, class _S>
bool chmin(F &u, const _S &v){
    bool flag = false;
    if ( u > v ){
        u = v; flag |= true;
    }
    return flag;
}

template <class F, class _S>
bool chmax(F &u, const _S &v){
    bool flag = false;
    if ( u < v ){
        u = v; flag |= true;
    }
    return flag;
}

struct frac{
    int a, b;

    frac(int a = 0, int b = 1) : a(a), b(b) {}

    bool operator <=(const frac &t){
        return a * t.b <= b * t.a;
    }
};

signed main(){
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);

    int n, h; cin >> n >> h;
    vector <int> x(n), y(n);
    for ( int i = 0; i < n; i++ ){
        cin >> x[i] >> y[i];
    }
    auto ok = [&](int i, int j, int k, int s){
        return (x[j] - x[i]) * (y[k] - y[i]) * s >= (x[k] - x[i]) * (y[j] - y[i]) * s;
    };
    vector <frac> L(n / 2), R(n / 2);
    deque <int> dq;
    dq.pb(0);
    for ( int i = 1; i + 1 < n; i++ ){
        while ( dq.size() > 1 && ok(dq[(int)dq.size() - 2], dq.back(), i, 1) ){
            dq.pop_back();
        }
        if ( i % 2 == 0 ){
            int j = dq.back();
            int a = y[j] - y[i], b = x[j] - x[i];
            L[i / 2 - 1] = frac((h - y[i]) * b + a * x[i], a);
        } dq.pb(i);
    }
    dq.clear();
    dq.pb(n - 1);
    for ( int i = n - 2; i > 0; i-- ){
        while ( dq.size() > 1 && ok(dq[1], dq[0], i, -1) ){
            dq.pop_front();
        }
        if ( i % 2 == 0 ){
            int j = dq.front();
            int a = y[j] - y[i], b = x[j] - x[i];
            R[i / 2 - 1] = frac((h - y[i]) * b + a * x[i], a);
        } dq.push_front(i);
    }
    int ans = 1, N = 1e7;
    for ( int i = 0; i < n / 2; i++ ){
        if ( !L[i].b ){
            L[i] = {-N, 1};
        }
        if ( !R[i].b ){
            R[i] = {N, 1};
        }
    }
    cout << (n > 3);
    return 0;
    frac lst = R[0];
    for ( int i = 1; i < n / 2; i++ ){
        if ( L[i] <= lst ){
            if ( R[i] <= lst ){
                lst = R[i];
            }
        } else{
            ans++;
            lst = R[i];
        }
    }
    cout << ans;

    cout << '\n';
}

• Subtask 1: 0 / 20
• Subtask 2: 0 / 30
• Subtask 3: 0 / 60