Submission #9484

#	Submission time	Handle	Problem	Language	Result	Execution time	Memory
9484	2014-09-28T06:47:11 Z	lhch6759	N-orthotope (kriii2_N)	C++	0 / 4	0 ms	1672 KB

N

// 제2회 kriiICPC
// 
// 

#include <iostream>
#include <vector>

using namespace std;


int main(){

	int case_num;
	cin >> case_num;

	int A[12][2];
	int B[12][2];
	int orthotope[12]; //안겹칠 경우 -1, 한점에서 만나는경우 0, 선이 겹치는 경우 1
	
	//input
	for (int nc = 0; nc < case_num; nc++){
		orthotope[nc] = -1;
	
		for (int n = 0; n < 2; n++){
			cin >> A[nc][n];	
		}
	}
	for (int nc = 0; nc < case_num; nc++){
		for (int n = 0; n < 2; n++){
			cin >> B[nc][n];
		}
	}
	
	//
	
	for (int i = 0; i < case_num; i++){

		// 선분으로 만난 경우
		if (A[i][1] <= B[i][1] && B[i][0] <= A[i][1]
			) orthotope[i] = 1; //A[i][1]

		if (B[i][0] <= A[i][0] && A[i][0] <= B[i][1]
			) orthotope[i] = 1; // A[i][0]

		if (B[i][0] >= A[i][0] && B[i][0] <= A[i][1] 
			) orthotope[i] = 1; // B[i][0]
		if (B[i][1] <= A[i][1] && B[i][1] >= A[i][0]
			) orthotope[i] = 1; // B[i][1]

		// 점으로 만난 경우
		if (A[i][1] == B[i][0])  orthotope[i] = 0; //B[i][0]
		if (B[i][1] == A[i][0])  orthotope[i] = 0; //A[i][0]
		if ( orthotope[i] == 1 && 
			( A[i][0] == A[i][1] || B[i][0] == B[i][1] ))  orthotope[i] = 0;
	}
	int result = -1;
	for (int i = 0; i < case_num; i++){
		if (orthotope[i] > 0){
			if (result == -1) result = 0;
			result++;
		}
	}
	
	if (result == -1){
		for (int i = 0; i < case_num; i++){
			if (orthotope[i] == 0) result = 0;
		}
	}
	cout << result << endl;

	
}

Subtask #1

0.0 / 1.0

#	Verdict	Execution time	Memory	Grader output
1	Correct	0 ms	1672 KB	Output is correct
2	Correct	0 ms	1672 KB	Output is correct
3	Correct	0 ms	1672 KB	Output is correct
4	Correct	0 ms	1672 KB	Output is correct
5	Correct	0 ms	1672 KB	Output is correct
6	Correct	0 ms	1672 KB	Output is correct
7	Incorrect	0 ms	1672 KB	Output isn't correct
8	Halted	0 ms	0 KB	-

Subtask #2

0.0 / 3.0

#	Verdict	Execution time	Memory	Grader output
1	Halted	0 ms	0 KB	-