# | Submission time | Handle | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
944514 | 2024-03-12T20:58:29 Z | rainboy | 제곱근 구하기 1 (gs13068_sqrt1) | C | 0 ms | 0 KB |
#include <math.h> #include <stdio.h> int main() { long long n; int r; scanf("%lld", &n), r = sqrt(n); while ((long long) (r + 1) * (r + 1) <= n) r++; while ((long long) r * r > n) r--; printf("%f\n", r + (double) (n - (long long) r * r) / (r * 2 + 1)); return 0; }